On a N * N
grid, we place some 1 * 1 * 1
cubes.java
Each value v = grid[i][j]
represents a tower of v cubes placed on top of grid cell (i, j)
.3d
Return the total surface area of the resulting shapes.调试
Example 1:code
Input: [[2]] Output: 10
Example 2:leetcode
Input: [[1,2],[3,4]] Output: 34
Example 3:get
Input: [[1,0],[0,2]] Output: 16
Example 4:io
Input: [[1,1,1],[1,0,1],[1,1,1]] Output: 32
Example 5:class
Input: [[2,2,2],[2,1,2],[2,2,2]] Output: 46
Note:grid
1 <= N <= 50
0 <= grid[i][j] <= 50
题目地址top
这道题感受还挺难的,不该该放在简单题里面。主要是考察分类讨论的能力,corner case很是之多,对分类讨论的能力要求很高。调试很久才过。
class Solution { public int surfaceArea(int[][] grid) { int result = 0; for(int i=0;i<grid.length;i++){ for(int j=0;j<grid.length;j++){ if(i==0){ if(j==0){ if(grid[i][j]<=1){ result += 6*grid[i][j]; }else{ result += 6+4*(grid[i][j]-1); } }else{ if(grid[i][j]<=1){ result += grid[i][j]*6-2*(Math.min(grid[i][j],grid[i][j-1])); }else{ result += 6+4*(grid[i][j]-1)-2*(Math.min(grid[i][j],grid[i][j-1])); } } }else{ if(j==0){ if(grid[i][j]<=1){ result += grid[i][j]*6-2*(Math.min(grid[i][j],grid[i-1][j])); }else{ result += 6+4*(grid[i][j]-1)-2*(Math.min(grid[i][j],grid[i-1][j])); } }else{ if(grid[i][j]<=1){ result += grid[i][j]*6-2*(Math.min(grid[i][j],grid[i-1][j]))-2*(Math.min(grid[i][j],grid[i][j-1])); }else{ result += 6+4*(grid[i][j]-1)-2*(Math.min(grid[i][j],grid[i-1][j]))-2*(Math.min(grid[i][j],grid[i][j-1])); } } } } } return result; } }