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In a project, you have a list of required skills req_skills
, and a list of people
. The i-th person people[i]
contains a list of skills that person has.java
Consider a sufficient team: a set of people such that for every required skill in req_skills
, there is at least one person in the team who has that skill. We can represent these teams by the index of each person: for example, team = [0, 1, 3]
represents the people with skills people[0]
, people[1]
, and people[3]
.node
Return any sufficient team of the smallest possible size, represented by the index of each person.react
You may return the answer in any order. It is guaranteed an answer exists. git
Example 1:github
Input: req_skills = ["java","nodejs","reactjs"], people = [["java"],["nodejs"],["nodejs","reactjs"]] Output: [0,2]
Example 2:微信
Input: req_skills = ["algorithms","math","java","reactjs","csharp","aws"], people = [["algorithms","math","java"],["algorithms","math","reactjs"],["java","csharp","aws"],["reactjs","csharp"],["csharp","math"],["aws","java"]] Output: [1,2]
Constraints:app
1 <= req_skills.length <= 16
1 <= people.length <= 60
1 <= people[i].length, req_skills[i].length, people[i][j].length <= 16
req_skills
and people[i]
are (respectively) distinct.req_skills[i][j], people[i][j][k]
are lowercase English letters.做为项目经理,你规划了一份需求的技能清单 req_skills
,并打算从备选人员名单 people
中选出些人组成一个「必要团队」( 编号为 i
的备选人员 people[i]
含有一份该备选人员掌握的技能列表)。ide
所谓「必要团队」,就是在这个团队中,对于所需求的技能列表 req_skills
中列出的每项技能,团队中至少有一名成员已经掌握。ui
咱们能够用每一个人的编号来表示团队中的成员:例如,团队 team = [0, 1, 3]
表示掌握技能分别为 people[0]
,people[1]
,和 people[3]
的备选人员。
请你返回 任一 规模最小的必要团队,团队成员用人员编号表示。你能够按任意顺序返回答案,本题保证答案存在。
示例 1:
输入:req_skills = ["java","nodejs","reactjs"], people = [["java"],["nodejs"],["nodejs","reactjs"]] 输出:[0,2]
示例 2:
输入:req_skills = ["algorithms","math","java","reactjs","csharp","aws"], people = [["algorithms","math","java"],["algorithms","math","reactjs"],["java","csharp","aws"],["reactjs","csharp"],["csharp","math"],["aws","java"]] 输出:[1,2]
提示:
1 <= req_skills.length <= 16
1 <= people.length <= 60
1 <= people[i].length, req_skills[i].length, people[i][j].length <= 16
req_skills
和 people[i]
中的元素分别各不相同req_skills[i][j], people[i][j][k]
都由小写英文字母组成1 class Solution { 2 func smallestSufficientTeam(_ req_skills: [String], _ people: [[String]]) -> [Int] { 3 var solution = Set<Int>() 4 var setPeople = people.map { Set($0) } 5 var skillToPeopleDict = [String:[Int]]() 6 7 for (i, personSet) in setPeople.enumerated() { 8 for (j, anotherPersonSet) in setPeople.enumerated() where i != j { 9 if personSet.isSubset(of: anotherPersonSet) { 10 setPeople[i] = [] 11 break 12 } 13 } 14 } 15 16 for (i, personSet) in setPeople.enumerated() { 17 for skill in personSet { 18 skillToPeopleDict[skill] = (skillToPeopleDict[skill] ?? []) + [i] 19 } 20 } 21 22 return smallestSufficientTeam(req_skills, skillToPeopleDict, setPeople, 0, [], []) 23 } 24 25 func smallestSufficientTeam(_ skills: [String], 26 _ skillToPeopleDict: [String:[Int]], 27 _ people: [Set<String>], 28 _ i: Int, 29 _ totalSkillsAdded: Set<String>, 30 _ soFar: [Int]) -> [Int] { 31 if i >= skills.count { return Array(soFar) } 32 33 let nextSkill = skills[i] 34 35 if totalSkillsAdded.contains(nextSkill) { 36 return smallestSufficientTeam(skills, skillToPeopleDict, people, i+1, totalSkillsAdded, soFar) 37 } 38 39 var solution = [Int]() 40 41 for person in skillToPeopleDict[nextSkill] ?? [] { 42 let personSkills = people[person] 43 let next = smallestSufficientTeam(skills, 44 skillToPeopleDict, 45 people, 46 i+1, 47 totalSkillsAdded.union(personSkills), 48 soFar + [person]) 49 50 if !next.isEmpty { 51 if solution.isEmpty { 52 solution = next 53 } else if next.count < solution.count { 54 solution = next 55 } 56 } 57 } 58 59 return solution 60 } 61 }
156ms
1 class Solution { 2 func smallestSufficientTeam(_ req_skills: [String], _ people: [[String]]) -> [Int] { 3 let req_skills_len = req_skills.count, people_len = people.count 4 var map = [String: Int]() 5 for i in 0..<req_skills_len { 6 map[req_skills[i]] = i 7 } 8 var dp = [Int: [Int]]() 9 dp[0] = [Int]() 10 11 for i in 0..<people_len { 12 var his_skill = 0 13 for skill in people[i] { 14 if map[skill] != nil { 15 his_skill |= 1<<map[skill]! 16 } 17 } 18 for (skill_set, need) in dp { 19 let with_him = skill_set | his_skill 20 if with_him == skill_set { continue } 21 if dp[with_him] == nil || dp[with_him]!.count > need.count+1 { 22 var sets = need 23 sets.append(i) 24 dp[with_him] = sets 25 } 26 } 27 } 28 return dp[1<<req_skills_len - 1, default: [Int]()] 29 } 30 }
180ms
1 class Solution { 2 func smallestSufficientTeam(_ req_skills: [String], _ people: [[String]]) -> [Int] { 3 let n = req_skills.count 4 let m = people.count 5 var dict = [String: Int]() 6 for i in 0..<req_skills.count { 7 let skill = req_skills[i] 8 dict[skill] = i 9 } 10 11 var dp = [Int: [Int]]() 12 dp[0] = [Int]() 13 14 for (idx, skills) in people.enumerated() { 15 var his_skill = 0 16 for skill in skills { 17 his_skill |= 1 << dict[skill]! 18 } 19 20 for (skill_set, need) in dp { 21 let with_him = skill_set | his_skill 22 if with_him == skill_set { continue } 23 if dp[with_him] == nil || dp[with_him]!.count > need.count + 1 { 24 dp[with_him] = need + [idx] 25 } 26 } 27 } 28 return dp[(1<<n) - 1]! 29 } 30 }
296ms
1 class Solution { 2 struct Team { 3 public let people: [Int] 4 public let required: Set<String> 5 6 init(required: [String]) { 7 self.people = [] 8 self.required = Set<String>(required) 9 } 10 11 init(team: Team, adding idx: Int, with skills: [String]) { 12 self.people = team.people + [ idx ] 13 self.required = team.required.subtracting(skills) 14 } 15 } 16 17 private func completeTeam(_ team: Team, _ people: [[String]], _ bySkill: [String:[Int]]) -> Team? { 18 guard let skill = team.required.first else { 19 return team 20 } 21 guard let withSkill = bySkill[skill] else { 22 return nil 23 } 24 25 var bestTeam: Team? 26 var requiredUsed = Set<Set<String>>() 27 for idx in withSkill { 28 let tmpTeam = Team(team: team, adding: idx, with: people[idx]) 29 if requiredUsed.contains(tmpTeam.required) { 30 continue 31 } 32 requiredUsed.insert(tmpTeam.required) 33 34 guard let tmpResult = self.completeTeam(tmpTeam, people, bySkill) else { 35 continue 36 } 37 if bestTeam == nil || bestTeam!.people.count > tmpResult.people.count { 38 bestTeam = tmpResult 39 } 40 } 41 return bestTeam 42 } 43 44 func smallestSufficientTeam(_ req_skills: [String], _ people: [[String]]) -> [Int] { 45 guard req_skills.count > 0 && people.count > 0 else { 46 return [] 47 } 48 49 var bySkill = [String:[Int]]() 50 let team = Team(required: req_skills) 51 for (idx, skills) in people.enumerated() { 52 for skill in team.required.intersection(skills) { 53 bySkill[skill, default: []].append(idx) 54 } 55 } 56 57 if let result = self.completeTeam(team, people, bySkill) { 58 return result.people 59 } else { 60 return [] 61 } 62 } 63 }
Runtime: 652 ms
1 class Solution { 2 func smallestSufficientTeam(_ req_skills: [String], _ people: [[String]]) -> [Int] { 3 var inf:Int = 0x3f3f3f3f 4 let m:Int = req_skills.count 5 let n:Int = people.count 6 var all:Int = 1 << m 7 var skill_id:[String:Int] = [String:Int]() 8 var k:Int = 0 9 for skill in req_skills 10 { 11 skill_id[skill] = k 12 k += 1 13 } 14 var skillset:[Int] = [Int](repeating:0,count:n) 15 for i in 0..<n 16 { 17 var st:Int = 0 18 for skill in people[i] 19 { 20 st |= 1 << skill_id[skill]! 21 } 22 skillset[i] = st 23 } 24 var dp:[[Int]] = [[Int]](repeating:[Int](repeating:inf,count:all),count:n + 1) 25 var last:[[Int]] = [[Int]](repeating:[Int](repeating:0,count:all),count:n + 1) 26 dp[0][0] = 0 27 for i in 1...n 28 { 29 for j in 0..<all 30 { 31 if dp[i][j] > dp[i - 1][j] 32 { 33 dp[i][j] = dp[i - 1][j] 34 last[i][j] = j 35 } 36 if dp[i - 1][j] + 1 < dp[i][j | skillset[i - 1]] 37 { 38 dp[i][j | skillset[i - 1]] = dp[i - 1][j] + 1 39 last[i][j | skillset[i - 1]] = j 40 } 41 } 42 } 43 var i:Int = n 44 var j:Int = all - 1 45 var res:[Int] = [Int]() 46 while(i != 0) 47 { 48 if last[i][j] != j 49 { 50 res.insert(i - 1,at:0) 51 } 52 j = last[i][j] 53 i -= 1 54 } 55 return res 56 } 57 }