Codeforces Round #515 (Div. 3)-F. Yet another 2D Walking
地址：http://codeforces.com/contest/1066/problem/F 思路：贪心+DP：对于同一层的点，最佳的路线是从一端0走到另一端1，只要的选择是两层间的走法，只有四种走法，分别是从一层两端到另一层两端的走法。因此先求出所有层的步数，在用dp[i][j]来表示到第i层时在j端时的最小步数 Code: #include<iostream>
#include<algori
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