easyui datagrid 获取 title

        function exportExecl(obj) {
            var cfs = $(obj).datagrid('getColumnFields'); //这是获取到全部的Fields
            //获得title名
            var colName = [];
            for (i = 0; i < cfs.length; i++) {
                var col = $(obj).datagrid("getColumnOption", cfs[i]);
                colName.push(col.title);//把TITLEPUSH到数组里去
            }
            console.log(colName);
        }