python开发基础04-列表、元组、字典操做练习

练习1：

# l1    =  [11,22,33]
# l2   =  [22,33,44]
# a.    获取内容相同的元素列表
# b.    获取 l1  中有， l2 中没有的元素列表
# c.    获取 l2  中有， l1 中没有的元素列表
# d.    获取 l1  和 l2   中内容都不一样的元素

# l1    =    [11,22,33]
# l2    =    [22,33,44]
# for i in l2:
#     if i not in l1:
#         print(i)
# for i in l1:
#     if i not in l2:
#         print(i)

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练习2：

12345678互相组合为一个2位数，两位数值不可重复

 

# count =0
# for i in range(1, 9):
#     for v in range(1, 9):
#         if i !=v:
#             count += 1
# # count = count -8
# print(count)

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练习3：

99乘法表

# for i in range(1,10):
#     string = ""
#     for j in range(1,i+1):
#         string +=str(j) + " * "+str(i) + " = " +str(i*j)+"\t"
#     print(string)

方法1

# for i in range(1,10):
#     for j in range(1,i+1):
#         print(str(j) + " * "+str(i) + " = " +str(i*j)+"\t",end="")
#     print("\n",end="")

# 默认end=\n
# print('alex', end='11')
# print('alex','haifeng','gangniang',sep='11')

方法2

 

练习4：

[1,2,3,4]这里面的数字两个组合 多少种不一样样的，数字不重复的

# li = [1,2,3,4]
# l =len(li)
# for i in range(0,l-1):
#     for v in range(i+1,l):
#         print(li[i],li[v])

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练习5：

自动计算方案

百钱买小鸡

公鸡5文钱1只，母鸡三文钱一只，小鸡一文钱三只。如今用100文钱共买了100只鸡，

问这100只鸡中，公鸡，母鸡，小鸡各是多少只？ 

for x in range(1,100//5):
    for y in range(1,100//3):
        for z in range(1,100):
            if x + y + z == 100 and 5*x + 3*y + z/3 == 100:
                print(x,y,z)

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练习6：

 查找列表中元素，移除每一个元素的空格，并查找以 a 或 A 开头 而且以 c 结尾的全部元素。

　　li = ["alec", " aric", "Alex", "Tony", "rain"]

　　tu = ("alec", " aric", "Alex", "Tony", "rain")

　　dic = {'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}

#!/usr/bin/env python
# -*- coding:utf-8 -*-

li = ["alec", " aric", "Alex", "Tony", "rain"]

for S in li:
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)

tu = ("alec", " aric", "Alex", "Tony", "rain")

for S in tu:
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)


dic = {'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}

for S in dic.values():
S = S.strip()
prefix_a = S.startswith('a')
prefix_A = S.startswith('A')
suffix_c = S.endswith('c')
if prefix_a or prefix_A and suffix_c:
print('要查找的元素:%s' % S)

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练习7：

有以下变量，请实现要求的功能

tu = ("alex", [11, 22, {"k1": 'v1', "k2": ["age", "name"], "k3": (11,22,33)}, 44])

• 讲述元祖的特性

• 请问 tu 变量中的"k2"对应的值是什么类型？是否能够被修改？若是能够，请在其中添加一个元素 “Seven”

# 元组的一级元素不可被修改增长删除，有序，可迭代，可切片，可索引，可转换为列表。
tu = ("alex", [11, 22, {"k1": 'v1', "k2": ["age", "name"], "k3": (11,22,33)}, 44])
v = tu[1][2]["k2"]
v.append("Seven")
print(tu)

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