datetime

#用列表+循环实现，并包装成函数
def pySum(n):
    a = list(range(10))
    b = list(range(0, 50, 5))
    c = []
    for i in range(len(a)):
        c.append(a[i] ** 2 + b[i] ** 3)
    return(c)

print(pySum(10))


#用numpy实现，并包装成函数

import numpy
def npSum(n):
    a = numpy.arange(10)
    b = numpy.arange(0, 50, 5)
    c = a + b
    return(c)

print(npSum(10))



#对比两种方法实现的效率，给定一个较大参数n,用运行函数先后的timedelta表示
from datetime import  datetime
start = datetime.now()
pySum(100000)
delta = datetime.now()-start
print(delta)

start= datetime.now()
npSum(100000)
delta = datetime.now()-start
print(delta)

运行结果