Educational Codeforces Round 83 (Rated for Div. 2) C. Adding Powers

时间 2020-03-13

标签 educational codeforces rated div adding powers 栏目 CSS 繁體版

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传送门题意：思路：每步可加 k i k^i ki，也能够跳过不加，看可否构成给定数组数组中的0是不须要处理的咱们直接一步一步把数分解便可，看要用到的i是否够用，每一个i只能用一次作的过程：假设k=9，有一个数是b[i]= 9 3 + 9 4 + 9 5 9^3+9^4+9^5 93+94+95html int l=0;//要用的幂次 while(1){ while(b

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1. Educational Codeforces Round 83 (Rated for Div. 2) A - C
2. Educational Codeforces Round 83 (Rated for Div. 2)
3. Educational Codeforces Round 83 (Rated for Div. 2) D
4. Educational Codeforces Round 83 (Rated for Div. 2) B. Bogosort
5. 【A题】Educational Codeforces Round 83 (Rated for Div. 2)
6. Educational Codeforces Round 48 (Rated for Div. 2)
7. Educational Codeforces Round 67 (Rated for Div. 2)
8. Educational Codeforces Round 47 (Rated for Div. 2) 题解
9. Educational Codeforces Round 66 (Rated for Div. 2)
10. Educational Codeforces Round 107 (Rated for Div. 2)
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1. Educational Codeforces Round 83 (Rated for Div. 2) A - C
2. Educational Codeforces Round 83 (Rated for Div. 2)
3. Educational Codeforces Round 83 (Rated for Div. 2) D
4. Educational Codeforces Round 83 (Rated for Div. 2) B. Bogosort
5. 【A题】Educational Codeforces Round 83 (Rated for Div. 2)
6. Educational Codeforces Round 48 (Rated for Div. 2)
7. Educational Codeforces Round 67 (Rated for Div. 2)
8. Educational Codeforces Round 47 (Rated for Div. 2) 题解
9. Educational Codeforces Round 66 (Rated for Div. 2)
10. Educational Codeforces Round 107 (Rated for Div. 2)

>>更多相关文章<<