SQL经过绩效算薪酬

select sum(0.05*[yj]) as 提成,[dbo].[UserInfo].name as 员工名称 from [dbo].[Jxgl],[dbo].[UserInfo] where [dbo].[Jxgl].uid=[dbo].[UserInfo].uid group by [dbo].[UserInfo].name select [dbo].[departjob].dx as

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