目录python
若是咱们给出一个列表,咱们须要一次性取出多个值,咱们是否是能够用下面的方式实现呢?code
name_list = ['chen', 'python', 'jason'] x = name_list[0] y = name_list[1] z = name_list[2] print(f'x:{x}, y:{y}, z:{z}') #输出: x:chen, y:python, z:jason
解压缩能够这样理解:超市打包是把多个商品放在一块儿,解压缩其实就是解包把多个商品一次性拿出来。it
name_list = ['chen', 'python', 'jason'] x, y, z = name_list print(f'x:{x}, y:{y}, z:{z}') #输出: x:chen, y:python, z:jason
有时候咱们解压缩的值多是咱们不想要的,那么能够使用下划线,万能的下划线。class
name_list = ['chen', 'python', 'jason'] x, y, z = name_list x, _, z = name_list # _至关于告诉计算机不要了,不能以_开头和结尾 print(f'x:{x}, y:{y}, z:{z}') print(f'x:{x}, z:{z}') #输出: x:chen, y:python, z:jason x:chen, z:jason
字典的解压打包
dic = {"name":"chen","gender":"famale","age":18} x1,x2,x3 = dic print(x2) #输出: gender
还能够以下操做计算机
name_list = ['chen', 'python', 'jason','wang','lao'] x, y, _, _, z = name_list ## _是同样的 x,* _, z = name_list print(f'x:{x}, y:{y}, z:{z}') print(f'x:{x}, z:{z}') #输出: x:chen, y:python, z:lao x:chen, z:lao
python追求的是简洁性,代码不要写的太长了。所以字典也是能够的,可是字典解压缩的是key。di
info = {'name': 'chen', 'age': 18} x, y = info print(x, y) #输出: name age