如今不会用Promise都很差意思说本身是前端,Promise为何火起来,一句话解决了回调嵌套和执行顺序问题最重要的我感受是解决顺序问题。前端
不过开始写以前咱们先看看,promise怎么解决问题,怎么用。
列举一个顺序加载图片demo:promise
//需求 加载三张图片 img1,img2,img3,加载顺序是1,2,3 let url1 = "https://ss0.bdstatic.com/70cFvHSh_Q1YnxGkpoWK1HF6hhy/it/u=3293635140,3955114282&fm=26&gp=0.jpg" let url2 = "https://ss0.bdstatic.com/70cFuHSh_Q1YnxGkpoWK1HF6hhy/it/u=1019333328,1858047370&fm=26&gp=0.jpg" let url3 = "https://ss1.bdstatic.com/70cFvXSh_Q1YnxGkpoWK1HF6hhy/it/u=4226468334,723383513&fm=26&gp=0.jpg" let oImg1 = new Image() oImg1.onload = function() { console.log('img1加载完毕') let oImg2 = new Image() oImg2.onload = function() { console.log('img2加载完毕') let oImg3 = new Image() oImg3.onload = function() { console.log('img3加载完毕') console.log('所有加载完毕') } oImg3.src = url3 } oImg2.src = url2 } oImg1.src = url1
//结果没毛病url
接下来咱们试试promise怎么作,spa
function loadImg(url) { let img = new Image() img.src = url return new Promise((resolve, reject) => { img.onload = () => { console.log(url) resolve() } img.onerror = (e) => { reject(e) } }) } loadImg(url1).then(() => { return loadImg(url2) }).then(() => { return loadImg(url3) })
接下来再看看Promise.all,code
//需求 加载三张图片 img1,img2 所有加载完成作一些事情 let urls = ["https://ss0.bdstatic.com/70cFvHSh_Q1YnxGkpoWK1HF6hhy/it/u=3293635140,3955114282&fm=26&gp=0.jpg", "https://ss0.bdstatic.com/70cFuHSh_Q1YnxGkpoWK1HF6hhy/it/u=1019333328,1858047370&fm=26&gp=0.jpg" ] function loadImg(url) { let img = new Image() img.src = url return new Promise((resolve, reject) => { img.onload = () => { resolve(img) } img.onerror = (e) => { reject(e) } }) } function loadAll(arr) { let result = [] arr.forEach(item => { let p = loadImg(item).then((img) => { console.log(img) }) //存储当前Promise对象 console.log(p) result.push(p) }); Promise.all(result).then(() => { //所有完成 console.log("done") }).catch((err) => { // 有失败的状况 console.log(err) }); } loadAll(urls)
完成。。。对象