如何检查一个字符串在Objective-C中是否包含另外一个字符串？

如何检查字符串（ NSString ）是否包含另外一个较小的字符串？

我但愿有这样的东西：

NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);

可是我能找到的最接近的是：

if ([string rangeOfString:@"hello"] == 0) {
    NSLog(@"sub string doesnt exist");
} 
else {
    NSLog(@"exists");
}

不管如何，这是查找一个字符串是否包含另外一个字符串的最佳方法吗？

---

#1楼

NSString *myString = @"hello bla bla";
NSRange rangeValue = [myString rangeOfString:@"hello" options:NSCaseInsensitiveSearch];

if (rangeValue.length > 0)
{
    NSLog(@"string contains hello");
} 
else 
{
    NSLog(@"string does not contain hello!");
}

//您也能够使用如下方法：

if (rangeValue.location == NSNotFound) 
{
    NSLog(@"string does not contain hello");
} 
else 
{
    NSLog(@"string contains hello!");
}

---

#2楼

Oneliner（少许代码。DRY，由于您只有一个NSLog ）：

NSString *string = @"hello bla bla";
NSLog(@"String %@", ([string rangeOfString:@"bla"].location == NSNotFound) ? @"not found" : @"cotains bla");

---

#3楼

P i解决方案的改进版本（NSString上的类别）不只能够告诉您是否在另外一个字符串中找到了一个字符串，并且还能够经过引用获取一个范围：

@interface NSString (Contains)
-(BOOL)containsString: (NSString*)substring
              atRange:(NSRange*)range;

-(BOOL)containsString:(NSString *)substring;
@end

@implementation NSString (Contains)

-(BOOL)containsString:(NSString *)substring
              atRange:(NSRange *)range{

    NSRange r = [self rangeOfString : substring];
    BOOL found = ( r.location != NSNotFound );
    if (range != NULL) *range = r;
    return found;
}

-(BOOL)containsString:(NSString *)substring
{
    return [self containsString:substring
                        atRange:NULL];
}

@end

像这样使用它：

NSString *string = @"Hello, World!";

//If you only want to ensure a string contains a certain substring
if ([string containsString:@"ello" atRange:NULL]) {
    NSLog(@"YES");
}

// Or simply
if ([string containsString:@"ello"]) {
    NSLog(@"YES");
}

//If you also want to know substring's range
NSRange range;
if ([string containsString:@"ello" atRange:&range]) {
    NSLog(@"%@", NSStringFromRange(range));
}

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#4楼

这是一个复制粘贴功能代码段：

-(BOOL)Contains:(NSString *)StrSearchTerm on:(NSString *)StrText
{
    return [StrText rangeOfString:StrSearchTerm 
        options:NSCaseInsensitiveSearch].location != NSNotFound;
}

---

#5楼

因为这彷佛是Google的高排名结果，所以我想添加如下内容：

iOS 8和OS X 10.10将containsString:方法添加到NSString 。 这些系统的Dave DeLong示例的更新版本：

NSString *string = @"hello bla bla";
if ([string containsString:@"bla"]) {
    NSLog(@"string contains bla!");
} else {
    NSLog(@"string does not contain bla");
}