python 求天然对数的底数 e

#-*- coding: UTF-8 -*- ''' Created on 2011-3-3 @author: lihex 求天然对数的底数 e ''' #求阶乘 def factorial(number): if number==1: return 1 return number*factorial(number-1) #根据e^x 幂级数张开式，当x=1时

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