Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.code
You may assume no duplicates in the array.get
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0it
二分查找第一个大于等于的位置。io
耗时:9msclass
class Solution { public: int searchInsert(vector<int>& nums, int target) { return bsearch(nums, 0, nums.size(), target); } int bsearch(vector<int>& nums, int i, int j, int target) { if (i >= j) return i; if (i+1 == j) { return nums[i] < target ? i+1 : i;} int k = i + (j - i) / 2; int vk = nums[k]; if (vk == target) { return k; } else if (vk > target) { return bsearch(nums, i, k, target); } else { return bsearch(nums, k+1, j, target); } } };