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Given an array of integers nums
, write a method that returns the "pivot" index of this array.git
We define the pivot index as the index where the sum of the numbers to the left of the index is equal to the sum of the numbers to the right of the index.github
If no such index exists, we should return -1. If there are multiple pivot indexes, you should return the left-most pivot index.数组
Example 1:微信
Input: nums = [1, 7, 3, 6, 5, 6] Output: 3 Explanation: The sum of the numbers to the left of index 3 (nums[3] = 6) is equal to the sum of numbers to the right of index 3. Also, 3 is the first index where this occurs.
Example 2:app
Input: nums = [1, 2, 3] Output: -1 Explanation: There is no index that satisfies the conditions in the problem statement.
Note:this
nums
will be in the range [0, 10000]
.nums[i]
will be an integer in the range [-1000, 1000]
.给定一个整数类型的数组 nums
,请编写一个可以返回数组“中心索引”的方法。spa
咱们是这样定义数组中心索引的:数组中心索引的左侧全部元素相加的和等于右侧全部元素相加的和。code
若是数组不存在中心索引,那么咱们应该返回 -1。若是数组有多个中心索引,那么咱们应该返回最靠近左边的那一个。htm
示例 1:
输入: nums = [1, 7, 3, 6, 5, 6] 输出: 3 解释: 索引3 (nums[3] = 6) 的左侧数之和(1 + 7 + 3 = 11),与右侧数之和(5 + 6 = 11)相等。 同时, 3 也是第一个符合要求的中心索引。
示例 2:
输入: nums = [1, 2, 3] 输出: -1 解释: 数组中不存在知足此条件的中心索引。
说明:
nums
的长度范围为 [0, 10000]
。nums[i]
将会是一个范围在 [-1000, 1000]
的整数。140ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 if nums.count < 3 { 4 return -1 5 } 6 7 var sum = 0 8 for i in nums { 9 sum += i 10 } 11 12 var left = 0 13 var right = 0 14 15 for i in 0..<nums.count { 16 17 left = left + nums[i] 18 right = sum - left 19 20 if left - nums[i] == right { 21 return i 22 } 23 } 24 return -1 25 } 26 }
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 var sum:Int = nums.reduce(0,+) 4 var curSum:Int = 0 5 var n:Int = nums.count 6 for i in 0..<n 7 { 8 if sum - nums[i] == 2 * curSum 9 { 10 return i 11 } 12 curSum += nums[i] 13 } 14 return -1 15 } 16 }
156ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 guard nums.count > 0 else { 4 return -1 5 } 6 7 var leftSums: [Int] = [0] 8 var rightSums: [Int] = [0] 9 10 var sum: Int = nums.first! 11 for i in 1..<nums.count { 12 leftSums.append(sum) 13 let num = nums[i] 14 sum += num 15 } 16 17 sum = nums.last! 18 for i in (0..<nums.count - 1).reversed() { 19 rightSums.append(sum) 20 sum += nums[i] 21 } 22 23 rightSums = rightSums.reversed() 24 25 for i in 0..<nums.count { 26 if leftSums[i] == rightSums[i] { 27 return i 28 } 29 } 30 31 return -1 32 } 33 }
160ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 var numsLength = nums.count 4 guard numsLength != 0 else { return -1 } 5 6 var fromRight = Array(repeating: Int.min, count: numsLength) 7 fromRight[numsLength - 1] = nums[numsLength - 1] 8 var i = numsLength - 2 9 while i >= 0 { 10 fromRight[i] = nums[i] + fromRight[i + 1] 11 i -= 1 12 } 13 var fromLeft = 0 14 for i in 0..<(numsLength) { 15 var right = i + 1 < numsLength ? fromRight[i + 1] : 0 16 if fromLeft == right { 17 return i 18 } 19 fromLeft += nums[i] 20 21 } 22 return -1 23 } 24 }
172ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 var leftSum: Int = 0 4 var rightSum: Int = 0 5 6 for num in nums { 7 rightSum += num 8 } 9 10 for (index, value) in nums.enumerated() { 11 12 rightSum -= value 13 14 if leftSum == rightSum { 15 return index 16 } else { 17 leftSum += value 18 } 19 } 20 return -1 21 } 22 }
176ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 if nums.count <= 0{ 4 return -1 5 } 6 7 if nums.count == 1{ 8 return 0 9 } 10 11 // 计算和 12 var resunlt: Int = nums.reduce(0, +) 13 // 左边 14 var left: Int = 0 15 16 for i in 0...nums.count - 1 { 17 18 resunlt -= nums[i] 19 if i == 0 { 20 if resunlt == 0 { 21 return i 22 } 23 }else{ 24 left += nums[i - 1]; 25 if resunlt == left{ 26 return i 27 } 28 } 29 } 30 return -1 31 } 32 }
177ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 var index = -1 4 var numsSum = 0 5 for i in nums { 6 numsSum += i 7 } 8 var sum = 0 9 for j in 0..<nums.count { 10 if (numsSum - nums[j])%2 == 0 { 11 if sum == (numsSum - nums[j])/2 { 12 index = j 13 break 14 } 15 } 16 sum += nums[j] 17 } 18 return index 19 } 20 }
180ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 if nums.isEmpty { return -1 } 4 var sum = nums.reduce(0,+) 5 var leftSum = 0 6 for (index,element) in nums.enumerated() { 7 if leftSum == (sum - leftSum) - element { return index } 8 leftSum += element 9 } 10 return -1 11 } 12 }
224ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 4 var total = nums.reduce(0, +) 5 var sum = 0 6 7 for i in 0..<nums.count { 8 total -= nums[i] 9 if sum == total { 10 return i 11 } 12 sum += nums[i] 13 } 14 return -1 15 } 16 }
225ms
1 class Solution { 2 func pivotIndex(_ nums: [Int]) -> Int { 3 guard !nums.isEmpty else { return -1 } 4 5 var prefixSums = Array(repeating: 0, count: nums.count) 6 7 prefixSums[0] = nums[0] 8 for (i, num) in nums.enumerated().dropFirst() { 9 prefixSums[i] = prefixSums[i - 1] + num 10 } 11 12 for (i, prefixSum) in prefixSums.enumerated() { 13 let leftSum = prefixSum - nums[i] 14 let rightSum = prefixSums.last! - nums[i] - leftSum 15 16 if leftSum == rightSum { 17 return i 18 } 19 } 20 21 return -1 22 } 23 }