插入新的区间,涉及到区间的合并.
Note:code
Example:ip
Example 1: Input: intervals = [[1,3],[6,9]], newInterval = [2,5] Output: [[1,5],[6,9]] Example 2: Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8] Output: [[1,2],[3,10],[12,16]] Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].
class Solution { public: vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) { int n = intervals.size(), cur = 0; vector<vector<int>> res; while (cur < n && intervals[cur][1] < newInterval[0]) { res.push_back(intervals[cur++]); } while (cur < n && intervals[cur][0] <= newInterval[1]) { newInterval[0] = min(newInterval[0], intervals[cur][0]); newInterval[1] = max(newInterval[1], intervals[cur][1]); ++cur; } res.push_back(newInterval); while (cur < n) { res.push_back(intervals[cur++]); } return res; } };
第一个循环把不和给定新区间重叠的,应该放在新区间前面的区间先放在答案里
第二个循环处理有重叠的部分,一直到后边最后一个没有重叠了退出
最后一个循环将新区间后边的没有重叠的放到答案里get