C#浮点和双精度乘法返回整型的规律

float f=0.65f; int ret0 = (int)((float)(0.65f*20));//返回12 int ret1 = (int)((double)(0.65f*20));//返回12 int ret2 = (int)(0.65*20);//返回13 int ret3 = (int)(0.65f*20);//返回12 int ret4 = (int)

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