springMVC统一异常json输出

1 在springMVC.xml定义

<bean class="org.springframework.web.servlet.view.BeanNameViewResolver" />

 ／／必须 ，若是没有这个，它会找JSTLView, 报404错

<bea id="jsonView2" class="org.springframework.web.servlet.view.json.MappingJackson2JsonView" />

//若是有底下的InternalResourceViewResolver 必须放在后面

<bean class="com.zhihe.office.web.controller.SpringExceptionResolver" /> ／／自定义异常处理

     <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">

        <property name="prefix">

            <value>/WEB-INF/jsp/</value>

        </property>

        <property name="suffix">

            <value>.jsp</value>

        </property>

    </bean> 

2 SpringExceptionResolver.java

  

public class SpringExceptionResolver implements HandlerExceptionResolver{

 

    @Override

    public ModelAndView resolveException(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse, Object o, Exception e) {

        String url = httpServletRequest.getRequestURL().toString();

        ModelAndView mv;

        Map<String,String> map = new HashMap<String,String>();

        map.put("test", "test");

        mv = new ModelAndView("jsonView2", map);

        System.out.println("exception ok!");

        return mv;

    }

}