项目中不可避免会出现一些异常状况,而一个web项目,若不拦截异常,糟糕的状况下可能直接将堆栈抛给前端,从而致使各类鬼畜的问题前端
@ControllerAdvice
拦截异常给一个简单的demo,即可以很容易的了解这种手段如何处理了java
@ControllerAdvice @Slf4j @ResponseBody public class ActionExceptionHandler { @ExceptionHandler(value = Exception.class) public String defaultHandler(HttpServletRequest request, Exception e) { log.error("unexpected exception! request: {}, params: {} refer: {}, e: {}", request.getRequestURI(), request.getParameterMap(), request.getHeader("referer"), e); if (StringUtils.isBlank(e.getMessage())) { return ResponseWrapper.errorReturn(new Status(500, "内部异常")); } else { return ResponseWrapper.errorReturn(new Status(500, e.getMessage())); } } }
这里主要借助两个注解来实现,ControllerAdvice 和 ExceptionHandlerweb
尽信书则不如,已上内容,纯属一家之言,因本人能力通常,看法不全,若有问题,欢迎批评指正app