//C++数值类型的取值范围 #include "stdio.h" #include "iostream" using namespace std; int main() { char a1=-128;//-128~+127 short b1=-32768;// -32768~+32767 int c1=-2147483648;//-2147483648~+2147483647 long d1=-2147483648;//-2147483648~+2147483647 long long x1=-9223372036854775808;//-9223372036854775808~9223372036854775807 //如下取-1转化后为最大值 unsigned char a2=-1;//0~255 unsigned short b2=-1;// 0~65535 unsigned int c2=-1;//0~4294967295 unsigned long d2=-1;//0~4294967295 unsigned long long x2=-1;//0~18446744073709551615 float e=100/3.0;//10e±38,6位有效数字-7 double f=100.0/3;//10e±308,12位有效数字-16 long double g=100.0/3;//10±4932,15位有效数字-16 cout.precision(50); cout<<"测试平台:Intel P4,XPsp3-32bit,VC8.0"<<endl; cout<<"浮点数精度测试100除以3"<<endl; cout<<"float \t\t e="<<e<<endl; cout<<"double \t\t f="<<f<<endl; cout<<"long double \t g="<<g<<endl; cout<<"有符号数取最小值分别是"<<endl; printf("char a1 ->%d\n",a1); cout<<"short b1 ="<<b1<<endl; cout<<"int c1 ="<<c1<<endl; cout<<"long d1 ="<<d1<<endl; cout<<"long long x1 ="<<x1<<endl; cout<<"....最低值再减一,溢出得最大值"<<endl; a1--;b1--;c1--;d1--;x1--; printf("char a1 ->%d\n",a1); cout<<"short b1 ="<<b1<<endl; cout<<"int c1 ="<<c1<<endl; cout<<"long d1 ="<<d1<<endl; cout<<"long long x1 ="<<x1<<endl; cout<<"无符号数取最大值(-1)分别是"<<endl; printf("unsigned char a2 ->%d\n",a2); cout<<"unsigned short b2 ="<<b2<<endl; cout<<"unsigned int c2 ="<<c2<<endl; cout<<"unsigned long d2 ="<<d2<<endl; cout<<"unsigned long long x2 ="<<x2<<endl; cout<<"...最大值,加一后,溢出,归零(最小值)"<<endl; a2++;b2++;c2++;d2++;x2++; printf("unsigned char a2 ->%d\n",a2); cout<<"unsigned short b2 ="<<b2<<endl; cout<<"unsigned int c2 ="<<c2<<endl; cout<<"unsigned long d2 ="<<d2<<endl; cout<<"unsigned long long x2 ="<<x2<<endl; cout<<"....零减一后,又溢出,得最大值,因此别拿无数号数和小于0比"<<endl; a2--;b2--;c2--;d2--;x2--; printf("unsigned char a2 ->%d\n",a2); cout<<"unsigned short b2 ="<<b2<<endl; cout<<"unsigned int c2 ="<<c2<<endl; cout<<"unsigned long d2 ="<<d2<<endl; cout<<"unsigned long long x2 ="<<x2<<endl; cout<<"存储大小"<<endl; cout<<"sizeof(char) ="<<sizeof(char)<<"字节" <<endl; cout<<"sizeof(short) ="<<sizeof(short) <<"字节" <<endl; cout<<"sizeof(int) ="<<sizeof(int)<<"字节" <<endl; cout<<"sizeof(long) ="<<sizeof(long )<<"字节" <<endl; cout<<"sizeof(long long) ="<<sizeof(long long)<<"字节" <<endl<<endl; cout<<"sizeof(unsigned char) ="<<sizeof(unsigned char)<<"字节" <<endl; cout<<"sizeof(unsigned short) ="<<sizeof(unsigned short )<<"字节" <<endl; cout<<"sizeof(unsigned int) ="<<sizeof(unsigned int )<<"字节" <<endl; cout<<"sizeof(unsigned long) ="<<sizeof(unsigned long )<<"字节" <<endl; cout<<"sizeof(unsigned long long) ="<<sizeof(unsigned long long)<<"字节" <<endl<<endl; cout<<"sizeof(float) ="<<sizeof(float )<<"字节" <<endl; cout<<"sizeof(double) ="<<sizeof(double)<<"字节" <<endl; cout<<"sizeof(long double) ="<<sizeof(long double )<<"字节" <<endl; //其余方法#include "limits"//其余方法 /* cout<<"---------如下最大值--------------------"<<endl; cout<< numeric_limits<unsigned long long >::max() <<endl; cout<< numeric_limits< long long >::max() <<endl; cout<<"---------如下最小值--------------------"<<endl; cout<< numeric_limits<unsigned long long >::min() <<endl; cout<< numeric_limits<long long>::min() <<endl; */ //long long 取值-2E(sizeof(long long)*8)/2 ~ 2E(sizeof(long long)*8)-1 //unsigned long long 取值0~2E(sizeof(unsigned long long)*8)-1 return 0; }
测试结果:
浮点数精度测试100除以3
float e=33.33333206176757800000000000000
double f=33.33333333333333600000000000000
long double g=33.33333333333333600000000000000
有符号数取最小值分别是
char a1 ->-128
short b1 =-32768
int c1 =-2147483648
long d1 =-2147483648
long long x1 =-9223372036854775808
....最低值再减一,溢出得最大值
char a1 ->127
short b1 =32767
int c1 =2147483647
long d1 =2147483647
long long x1 =9223372036854775807
无符号数取最大值(-1)分别是
unsigned char a2 ->255
unsigned short b2 =65535
unsigned int c2 =4294967295
unsigned long d2 =4294967295
unsigned long long x2 =18446744073709551615
...最大值,加一后,溢出,归零(最小值)
unsigned char a2 ->0
unsigned short b2 =0
unsigned int c2 =0
unsigned long d2 =0
unsigned long long x2 =0
....零减一后,又溢出,得最大值,因此别拿无数号数和小于0比
unsigned char a2 ->255
unsigned short b2 =65535
unsigned int c2 =4294967295
unsigned long d2 =4294967295
unsigned long long x2 =18446744073709551615
存储大小
sizeof(char) =1字节
sizeof(short) =2字节
sizeof(int) =4字节
sizeof(long) =4字节
sizeof(long long) =8字节
sizeof(unsigned char) =1字节
sizeof(unsigned short) =2字节
sizeof(unsigned int) =4字节
sizeof(unsigned long) =4字节
sizeof(unsigned long long) =8字节
sizeof(float) =4字节
sizeof(double) =8字节
sizeof(long double) =8字节
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