1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)ide
例二:
select * from testtable
where numeber in (select number from people group by number having count(number) > 1 )
能够查出testtable表中number相同的记录

2
、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from
people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1
)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1
)

3
、查找表中多余的重复记录(多个字段)
select * from
vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1
)

4
、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from
vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1
)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1
)


5
、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from
vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1
)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1
)

(二)
比方说
在A表中存在一个字段“name”,
并且不一样记录之间的“name”值有可能会相同,
如今就是须要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) > 1

若是还查性别也相同大则以下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1


(三)
方法一

declare @max integer,@id integer

declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1

open
cur_rows

fetch cur_rows into @id,@max

while @@fetch_status=0

begin

select @max = @max -1

set rowcount @max

delete from 表名 where 主字段 = @id

fetch cur_rows into @id,@max

end

close
cur_rows

set rowcount 0

方法二

有两个意义上的重复记录,一是彻底重复的记录,也即全部字段均重复的记录,二是部分关键字段重复的记录,好比Name字段重复,而其余字段不必定重复或都重复能够忽略。

1
、对于第一种重复,比较容易解决,使用

select distinct * from
tableName

就能够获得无重复记录的结果集。

若是该表须要删除重复的记录(重复记录保留1条),能够按如下方法删除

select distinct * into #Tmp from
tableName

drop table
tableName

select * into tableName from
#Tmp

drop table
#Tmp

发生这种重复的缘由是表设计不周产生的,增长惟一索引列便可解决。

2
、这类重复问题一般要求保留重复记录中的第一条记录,操做方法以下

假设有重复的字段为Name,Address,要求获得这两个字段惟一的结果集

select identity(int,1,1) as autoID, * into #Tmp from
tableName

select min(autoID) as autoID into #Tmp2 from #Tmp group by
Name,autoID

select * from #Tmp where autoID in(select autoID from
#tmp2)

最后一个select即获得了Name,Address不重复的结果集(但多了一个autoID字段,实际写时能够写在select子句中省去此列)

(四)
查询重复

select * from tablename where id in
(

select id from
tablename

group by
id

having count(id) > 1

)