arr1中的每一项都是对象,arr2中的每一项也都是对象数组
const a = [ {_id: 1}, {_id: 2}, {_id: 3}, ]; const b = [ {_id: 2}, {_id: 4}, ]
解决方法一:code
const c = a.filter(x => !b.find(y => y._id === x._id)); // [ { _id: 1 }, { _id: 3} ]
解决方法二:对象
const c = a.filter(x => b.every(y => y._id !== x._id));