代码ios
#include <iostream> #include <stdio.h> #include <stdlib.h> #include <string> #include <string.h> using namespace std; char code[669][10002][70] = {0}; void Move_Str(char *Old) // 将字符串向前移动,每次判断的是队列的最前面的那一个 { { int i = 0; char temp[70] = {0}; while((*(Old+i)) != ' ' && (*(Old+i)) != 0) { i++; } memcpy(temp, Old+i+1, 70); memcpy(Old, temp, 70); return; } int change_num(char *start) // 将字符串中的那一段变成数字,一开始就是错在这里,没有话考虑到数字很大 { int num_temp = 0, i = 0; char str_temp[10] = {0}; while(*(start+i) != ' ' && *(start+i) != 0) { str_temp[i] = *(start+i); i++; } str_temp[i] = 0; num_temp = atoi(str_temp); return num_temp; } int main() { int T = 0, n = 0; cin >> T; cin >> n; getchar(); int i = 0, j = 0, flag = 0, temp_num = 0, unlock = 0; int Looked[10002] = {0}, k = 0; char str_temp[10] = {0}; for(i = 0; i< T; i++) { for(j = 0; j< n; j++) { gets(code[i][j]); //cout << code[i][j] << endl; } } for(i = 0; i<T; i++) { while(1) { flag = 0; unlock = 0; for(j = 0; j< n; j++) { Looked[j] = 0; // 将 Looked数组初始化 if(code[i][j][0] != 0) flag = 1; } if(flag == 0) { cout << 0 << endl; break; // 表示所有都完成了,也就是不会发生死锁 } // 判断是不是死锁啊 for(j = 0; j< n; j++) { if(Looked[j] == 1) continue; if(code[i][j][0] == 'R') { temp_num = change_num(code[i][j]+1); if(code[i][temp_num][0] == 'S' && ((change_num(code[i][temp_num]+1)) == j)) { Move_Str(code[i][j]); Move_Str(code[i][temp_num]); unlock = 1; Looked[j] = 1; Looked[temp_num] = 1; // 这样是不会死锁的 } } else { temp_num = change_num(code[i][j]+1); if(code[i][temp_num][0] == 'R' && ((change_num(code[i][temp_num]+1)) == j)) { Move_Str(code[i][j]); Move_Str(code[i][temp_num]); unlock = 1; Looked[j] = 1; Looked[temp_num] = 1; // 这样是不会死锁的 } } } if(unlock == 0) { cout << 1 << endl; break; // 表示死锁了 } } } return 0; }