对于JSON格式的数据交互,想必你们不会陌生。JSON(全称JavaScript Object Notation, JS 对象简谱) 是一种轻量级的数据交换格式,JSON由于具备易于人阅读和编写,同时也易于机器解析和生成,并有效地提高网络传输效率等特性,一般被用在客户端与服务端的数据交互中。git
对于JSON的基本知识,本文不作详细介绍,读者能够自行搜索资料进行学习。github
手动解析一般应用在一些基本简单的场合,即数据结构不是很复杂的场景,手动解析JSON是指使用Flutter提供的dart:convert
中内置的JSON解码器。它可以将原始JSON字符串传递给json.decode() 方法,而后在返回的Map<String, dynamic>中查找所需的值。 它不须要依赖任何第三方库,对于小项目来讲很方便。web
例如,有下面一个接口:jsonplaceholder.typicode.com/posts/1,它的数…json
{
"userId": 1,
"id": 1,
"title": "sunt aut facere repellat provident occaecati excepturi optio reprehenderit",
"body": "quia et suscipit\nsuscipit recusandae consequuntur expedita et cum\nreprehenderit molestiae ut ut quas totam\nnostrum rerum est autem sunt rem eveniet architecto"
}
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因为上面的数据格式比较简单,所以咱们可使用手动解析的方式来解析它。bash
final responseJson = json.decode(response.body);
Map<String, dynamic> newTitle = responseJson ;
print(newTitle['title']);//打印title的值
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固然,咱们也能够新建一个实体类,而后将它解析到实体类中。网络
final responseJson = json.decode(response.body);
print(responseJson.toString());
Post postBean = Post.fromJson(responseJson); //Post为实体类
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对于数据结构不是很复杂的时候,使用fromJson来解析字段还好,可是若是数据结构比较复杂的话,手写fromJson、toJson就不太友好,而且容易出错。数据结构
在Android原生开发中,咱们可使用诸如Gson、FastJson等第三方库来帮助咱们将JSON数据转成实体类。一样,在Flutter开发中,咱们也可使用插件或工具来一键生成实体类。async
例如,下面是豆瓣电影提供的获取电影列表的一个接口,数据返回的格式以下:ide
{
count: 10,
start: 25,
total: 250,
subjects: [
{
rating: {
max: 10,
average: 9.1,
details: {
},
stars: "45",
min: 0
},
genres: [
"剧情",
"动做",
"科幻"
],
title: "蝙蝠侠:黑暗骑士",
casts: [
{
avatars: {
small: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p1004.webp",
large: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p1004.webp",
medium: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p1004.webp"
},
name_en: "Christian Bale",
name: "克里斯蒂安·贝尔",
alt: "https://movie.douban.com/celebrity/1005773/",
id: "1005773"
},
{
avatars: {
small: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p13801.webp",
large: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p13801.webp",
medium: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p13801.webp"
},
name_en: "Heath Ledger",
name: "希斯·莱杰",
alt: "https://movie.douban.com/celebrity/1006957/",
id: "1006957"
},
{
avatars: {
small: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p522.webp",
large: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p522.webp",
medium: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p522.webp"
},
name_en: "Aaron Eckhart",
name: "艾伦·艾克哈特",
alt: "https://movie.douban.com/celebrity/1053577/",
id: "1053577"
}
],
durations: [
"152分钟"
],
collect_count: 813292,
mainland_pubdate: "",
has_video: true,
original_title: "The Dark Knight",
subtype: "movie",
directors: [
{
avatars: {
small: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p673.webp",
large: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p673.webp",
medium: "http://img1.doubanio.com/view/celebrity/s_ratio_celebrity/public/p673.webp"
},
name_en: "Christopher Nolan",
name: "克里斯托弗·诺兰",
alt: "https://movie.douban.com/celebrity/1054524/",
id: "1054524"
}
],
pubdates: [
"2008-07-14(纽约首映)",
"2008-07-18(美国)"
],
year: "2008",
images: {
small: "http://img1.doubanio.com/view/photo/s_ratio_poster/public/p462657443.webp",
large: "http://img1.doubanio.com/view/photo/s_ratio_poster/public/p462657443.webp",
medium: "http://img1.doubanio.com/view/photo/s_ratio_poster/public/p462657443.webp"
},
alt: "https://movie.douban.com/subject/1851857/",
id: "1851857"
},
title: "豆瓣电影Top250"
}
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若是咱们使用fromJson、toJson来进行解析的话,就比较麻烦,而且还容易出错,所以咱们使用一些工具来辅助进行JSON解析。工具
首先,打开JSON to Dart,以下图所示。
Cannot generate dart code. Please check the project caveats.
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以下图:
除了上面的方式外,咱们还可使用FlutterJsonBeanFactory插件来辅助生成Bean类。 安装FlutterJsonBeanFactory插件很简单,以Android Studio为例,依次选择【Android Studio】->【Preferences…】->【Plugins】,而后搜索FlutterJsonBeanFactory插件安装便可,以下图所示。
须要说明的是,生成实体类时,类名后面的entity是自动加上去的,能够在设置中配置自定义名称,以下图。
//获取电影列表
void getFilmList() async {
Dio dio = new Dio();
Response response=await dio.get(hotMovies);
print('电影数据:'+response.toString());
Map userMap = json.decode(response.toString());
var movies = new MoviesEntity.fromJson(userMap);
}
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