使用RestTemplate Spring安全认证
java spring 认证authentication 安全spring-security
我有提供2个独立的一整套服务2 Spring的web应用程序。 Web应用程序1具备Spring Security的使用认证。 如今，Web应用程序2须要访问Web应用程序1的服务。一般状况下，咱们的RestTemplate类来发送请求到其余网络服务。 咱们如何经过在Web应用程序2要求的身份
验证凭据到Web应用程序1
本文地址 ：CodeGo.net/238843/
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1. 我当时的状况。这里有个人解决方案。 服务器-春季安全配置
<sec:http>
<sec:intercept-url pattern="/**" access="ROLE_USER" method="POST"/>
<sec:intercept-url pattern="/**" filters="none" method="GET"/>
<sec:http-basic />
</sec:http>
<sec:authentication-manager alias="authenticationManager">
<sec:authentication-provider>
<sec:user-service>
<sec:user name="${rest.username}" password="${rest.password}" authorities="ROLE_USER"/>
</sec:user-service>
</sec:authentication-provider>
</sec:authentication-manager> 客户端端RestTemplate配置
<bean id="httpClient" class="org.apache.commons.httpclient.HttpClient">
<constructor-arg ref="httpClientParams"/>
<property name="state" ref="httpState"/>
</bean>
<bean id="httpState" class="CustomHttpState">
<property name="credentials" ref="credentials"/>
</bean>
<bean id="credentials" class="org.apache.commons.httpclient.UsernamePasswordCredentials">
<constructor-arg value="${rest.username}"/>
<constructor-arg value="${rest.password}"/>
</bean>
<bean id="httpClientFactory" class="org.springframework.http.client.CommonsClientHttpRequestFactory">
<constructor-arg ref="httpClient"/>
</bean>
<bean class="org.springframework.web.client.RestTemplate">
<constructor-arg ref="httpClientFactory"/>
</bean> 自定义的HttpState
/**
* Custom implementation of {@link HttpState} with credentials property.
*
* @author banterCZ
*/
public class CustomHttpState extends HttpState {
/**
* Set credentials property.
*
* @param credentials
* @see #setCredentials(org.apache.commons.httpclient.auth.AuthScope, org.apache.commons.httpclient.Credentials)
*/
public void setCredentials(final Credentials credentials) {
super.setCredentials(AuthScope.ANY, credentials);
}
} Maven的依赖
<dependency>
<groupId>commons-httpclient</groupId>
<artifactId>commons-httpclient</artifactId>
<version>3.1</version>
</dependency>
2. 这里是一个解决方案，它工做得很好，春季3.1和Apache HttpComponents 4.1我建立了这个网站为基础的答案和阅读的springRestTempalte源代码。我在救人的但愿分享我以为spring应该只是有这样的内置代码，但它没有。
RestClient client = new RestClient();
client.setApplicationPath("someApp");
String url = client.login("theuser", "123456");
UserPortfolio portfolio = client.template().getForObject(client.apiUrl("portfolio"),
UserPortfolio.class); 下面是设置了HttpComponents上下文是工厂类上与RestTemplate每一个请求。
public class StatefullHttpComponentsClientHttpRequestFactory extends
HttpComponentsClientHttpRequestFactory
{
private final HttpContext httpContext;
public StatefullHttpComponentsClientHttpRequestFactory(HttpClient httpClient, HttpContext httpContext)
{
super(httpClient);
this.httpContext = httpContext;
}
@Override
protected HttpContext createHttpContext(HttpMethod httpMethod, URI uri)
{
return this.httpContext;
}
} 下面是有状态的
rest模板，你的cookies，一旦你与它会将JSESSIONID登陆并发送它在后续的请求。
public class StatefullRestTemplate extends RestTemplate
{
private final HttpClient httpClient;
private final CookieStore cookieStore;
private final HttpContext httpContext;
private final StatefullHttpComponentsClientHttpRequestFactory statefullHttpComponentsClientHttpRequestFactory;
public StatefullRestTemplate()
{
super();
httpClient = new DefaultHttpClient();
cookieStore = new BasicCookieStore();
httpContext = new BasicHttpContext();
httpContext.setAttribute(ClientContext.COOKIE_STORE, getCookieStore());
statefullHttpComponentsClientHttpRequestFactory = new StatefullHttpComponentsClientHttpRequestFactory(httpClient, httpContext);
super.setRequestFactory(statefullHttpComponentsClientHttpRequestFactory);
}
public HttpClient getHttpClient()
{
return httpClient;
}
public CookieStore getCookieStore()
{
return cookieStore;
}
public HttpContext getHttpContext()
{
return httpContext;
}
public StatefullHttpComponentsClientHttpRequestFactory getStatefulHttpClientRequestFactory()
{
return statefullHttpComponentsClientHttpRequestFactory;
}
} 这里是一个类来表示一个
REST客户端端，让你能够调用抵押和spring有个应用程序安全性。
public class RestClient
{
private String host = "localhost";
private String port = "8080";
private String applicationPath;
private String apiPath = "api";
private String loginPath = "j_spring_security_check";
private String logoutPath = "logout";
private final String usernameInputFieldName = "j_username";
private final String passwordInputFieldName = "j_password";
private final StatefullRestTemplate template = new StatefullRestTemplate();
/**
* This method logs into a service by doing an standard http using the configuration in this class.
*
* @param username
* the username to log into the application with
* @param password
* the password to log into the application with
*
* @return the url that the login redirects to
*/
public String login(String username, String password)
{
MultiValueMap<String, String> form = new LinkedMultiValueMap<>();
form.add(usernameInputFieldName, username);
form.add(passwordInputFieldName, password);
URI location = this.template.postForLocation(loginUrl(), form);
return location.toString();
}
/**
* Logout by doing an http get on the logout url
*
* @return result of the get as ResponseEntity
*/
public ResponseEntity<String> logout()
{
return this.template.getForEntity(logoutUrl(), String.class);
}
public String applicationUrl(String relativePath)
{
return applicationUrl() + "/" + checkNotNull(relativePath);
}
public String apiUrl(String relativePath)
{
return applicationUrl(apiPath + "/" + checkNotNull(relativePath));
}
public StatefullRestTemplate template()
{
return template;
}
public String serverUrl()
{
return " CodeGo.net + host + ":" + port;
}
public String applicationUrl()
{
return serverUrl() + "/" + nullToEmpty(applicationPath);
}
public String loginUrl()
{
return applicationUrl(loginPath);
}
public String logoutUrl()
{
return applicationUrl(logoutPath);
}
public String apiUrl()
{
return applicationUrl(apiPath);
}
public void setLogoutPath(String logoutPath)
{
this.logoutPath = logoutPath;
}
public String getHost()
{
return host;
}
public void setHost(String host)
{
this.host = host;
}
public String getPort()
{
return port;
}
public void setPort(String port)
{
this.port = port;
}
public String getApplicationPath()
{
return applicationPath;
}
public void setApplicationPath(String contextPath)
{
this.applicationPath = contextPath;
}
public String getApiPath()
{
return apiPath;
}
public void setApiPath(String apiPath)
{
this.apiPath = apiPath;
}
public String getLoginPath()
{
return loginPath;
}
public void setLoginPath(String loginPath)
{
this.loginPath = loginPath;
}
public String getLogoutPath()
{
return logoutPath;
}
@Override
public String toString()
{
StringBuilder builder = new StringBuilder();
builder.append("RestClient [\n serverUrl()=");
builder.append(serverUrl());
builder.append(", \n applicationUrl()=");
builder.append(applicationUrl());
builder.append(", \n loginUrl()=");
builder.append(loginUrl());
builder.append(", \n logoutUrl()=");
builder.append(logoutUrl());
builder.append(", \n apiUrl()=");
builder.append(apiUrl());
builder.append("\n]");
return builder.toString();
}
}
3. 该RestTemplate是很是基本的和有限的 CodeGo.net，彷佛没有成为一个简单的方法来作到这一点。最好的办法多是在Web应用程序1消化基自己份
验证的。 Apache的HttpClient的直接从Web应用程序2访问
REST服务。 话虽这么说，对于测试我能解决这个一个大劈。基本上，RestTemplate提交登陆（j_spring_security_check），解析出JSESSIONID从请求头，而后提交，其他请求。下面的代码，但我怀疑它是为生产作好准备代码的最佳解决方案。
public final class RESTTest {
public static void main(String[] args) {
RestTemplate rest = new RestTemplate();
HttpsURLConnection.setDefaultHostnameVerifier(new HostnameVerifier() {
@Override
public boolean verify(String s, SSLSession sslsession) {
return true;
}
});
// setting up a trust store with JCA is a whole other issue
// this assumes you can only log in via SSL
// you could turn that off, but not on a production site!
System.setProperty("javax.net.ssl.trustStore", "/path/to/cacerts");
System.setProperty("javax.net.ssl.trustStorePassword", "somepassword");
String jsessionid = rest.execute(" CodeGo.net HttpMethod.POST,
new RequestCallback() {
@Override
public void doWithRequest(ClientHttpRequest request) throws IOException {
request.getBody().write("j_username=user&j_password=user".getBytes());
}
}, new ResponseExtractor<String>() {
@Override
public String extractData(ClientHttpResponse response) throws IOException {
List<String> cookies = response.getHeaders().get("Cookie");
// assuming only one cookie with jsessionid as the only value
if (cookies == null) {
cookies = response.getHeaders().get("Set-Cookie");
}
String cookie = cookies.get(cookies.size() - 1);
int start = cookie.indexOf('=');
int end = cookie.indexOf(';');
return cookie.substring(start + 1, end);
}
});
rest.put(" CodeGo.net + jsessionid, new DAO("REST Test").asJSON());
} } 注意这个工做，你须要在JCA建立一个存储，以便在SSL链接实际上能够作。我不想让Spring Security的登陆是经过纯HTTP的生产现场，由于这将是一个巨大的安全漏洞。
4. 当前凭据应该能够在Web应用程序上1
Authentication对象，这是经过访问
SecurityContext（例如，你能够经过调用检索
SecurityContextHolder.getContext().getAuthentication()）。 当您检索凭据，您将它们访问Web应用程序2。 您能够经过扩展它与decorator（以下所述）通“Authentiation”头与RestTemplate
RestTemplate.exchange()方法，如在本论坛发表的文章中描述。
5. 有一个简单的方法来作到这一点的状况下，你是谁在寻找一个简单的调用，而不是一个API
HttpClient client = new HttpClient();
client.getParams().setAuthenticationPreemptive(true);
Credentials defaultcreds = new UsernamePasswordCredentials("username", "password");
RestTemplate restTemplate = new RestTemplate();
restTemplate.setRequestFactory(new CommonsClientHttpRequestFactory(client));
client.getState().setCredentials(AuthScope.ANY, defaultcreds);
本文标题 ：使用RestTemplate Spring安全认证
本文地址 ：CodeGo.net/238843/