Python zip()函数的一次踩坑记

测试一:python l1 = [1,2,3,4] l2 = [2,3,4,5] l3 = zip(l1,l2) for i in l3: print('for循环{}'.format(i)) l4=[x for x in l3] print(l4) 测试二:函数 l1 = [1,2,3,4] l2 = [2,3,4,5] l3 = zip(l1,l2) l4=[x for x in l
相关文章
相关标签/搜索