python计算100之内7的倍数和与个数

a = 0 count = 0 sz = [] num = 0 while a < 100: a += 1 if a%7 == 0: sz.append(a) count += 1 print("7的倍数是:",a) for i in range(len(sz)): num += sz[i] print("100之内有%s

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