编写一个 SQL 查询来实现分数排名。sql
若是两个分数相同,则两个分数排名(Rank)相同。请注意,平分后的下一个名次应该是下一个连续的整数值。换句话说,名次之间不该该有“间隔”。code
+----+-------+ | Id | Score | +----+-------+ | 1 | 3.50 | | 2 | 3.65 | | 3 | 4.00 | | 4 | 3.85 | | 5 | 4.00 | | 6 | 3.65 | +----+-------+
例如,根据上述给定的 Scores
表,你的查询应该返回(按分数从高到低排列):ip
+-------+------+ | Score | Rank | +-------+------+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +-------+------+
重要提示: 对于 MySQL 解决方案,若是要转义用做列名的保留字,能够在关键字以前和以后使用撇号。例如 `Rank`it
# Write your MySQL query statement below SELECT Score, DENSE_RANK() OVER(ORDER BY Score DESC) AS `Rank` FROM Scores;
DENSE_RANK、RANK、ROW_NUMBER 的使用说明io
Function | Description |
---|---|
DENSE_RANK | 并列连续排名 |
RANK | 并列跳跃排名 |
ROW_NUMBER | 连续排名 |
eg.table
-------------------------------------------------------- -- table_name: Scores -- -- +----+-------+ -- | id | score | -- +----+-------+ -- | 1 | 78 | -- | 2 | 89 | -- | 3 | 86 | -- | 4 | 91 | -- | 5 | 78 | -- | 6 | 89 | -- | 7 | 89 | -- +----+-------+ -------------------------------------------------------- -------------------------------------------------------- SELECT id, score, DENSE_RANK() OVER(ORDER BY score DESC) AS `DENSE_RANK`, RANK() OVER(ORDER BY score DESC) AS `RANK`, ROW_NUMBER() OVER(ORDER BY score DESC) AS `ROW_NUMBER` FROM Scores; -------------------------------------------------------- -------------------------------------------------------- -- result: -- -- +----+-------+------------+------+------------+ -- | id | score | DENSE_RANK | RANK | ROW_NUMBER | -- +----+-------+------------+------+------------+ -- | 4 | 91 | 1 | 1 | 1 | -- | 2 | 89 | 2 | 2 | 2 | -- | 6 | 89 | 2 | 2 | 3 | -- | 7 | 89 | 2 | 2 | 4 | -- | 3 | 86 | 3 | 5 | 5 | -- | 1 | 78 | 4 | 6 | 6 | -- | 5 | 78 | 4 | 6 | 7 | -- +----+-------+------------+------+------------+ --------------------------------------------------------