Navicat使用、pymysql模块（sql注入、增删改）

Navicat使用mysql

　　创建一张表 　　# 1. 测试+连接数据库 　　# 2. 新建库 　　# 3. 新建表，新增字段+类型+约束 　　# 4. 设计表：外键 　　# 5. 新建查询 　　# 6. 创建表模型

　　# 注意： 
　　　　批量加注释：ctrl+？键 
　　　　批量去注释：ctrl+shift+？键

　　如何导入SQL文件sql

　　拷贝如下代码，新建一个.sql文件，保存到桌面 　　打开navicat新建数据库day41，选中新建的数据库鼠标右键选择运行SQL文件 　　弹出文件框，选中刚刚保存到桌面的.sql文件便可

/* 数据导入： Navicat Premium Data Transfer Source Server : localhost Source Server Type : MySQL Source Server Version : 50624 Source Host : localhost Source Database : sqlexam Target Server Type : MySQL Target Server Version : 50624 File Encoding : utf-8 Date: 10/21/2016 06:46:46 AM */ SET NAMES utf8; SET FOREIGN_KEY_CHECKS = 0; -- ----------------------------
--  Table structure for `class` -- ---------------------------- DROP TABLE IF EXISTS `class`; CREATE TABLE `class` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `caption` varchar(32) NOT NULL, PRIMARY KEY (`cid`) ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; -- ----------------------------
--  Records of `class` -- ---------------------------- BEGIN; INSERT INTO `class` VALUES ('1', '三年二班'), ('2', '三年三班'), ('3', '一年二班'), ('4', '二年九班'); COMMIT; -- ----------------------------
--  Table structure for `course` -- ---------------------------- DROP TABLE IF EXISTS `course`; CREATE TABLE `course` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `cname` varchar(32) NOT NULL, `teacher_id` int(11) NOT NULL, PRIMARY KEY (`cid`), KEY `fk_course_teacher` (`teacher_id`), CONSTRAINT `fk_course_teacher` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`tid`) ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; -- ----------------------------
-- Records of `course` -- ---------------------------- BEGIN; INSERT INTO `course` VALUES ('1', '生物', '1'), ('2', '物理', '2'), ('3', '体育', '3'), ('4', '美术', '2'); COMMIT; -- ----------------------------
--  Table structure for `score` -- ---------------------------- DROP TABLE IF EXISTS `score`; CREATE TABLE `score` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `student_id` int(11) NOT NULL, `course_id` int(11) NOT NULL, `num` int(11) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_score_student` (`student_id`), KEY `fk_score_course` (`course_id`), CONSTRAINT `fk_score_course` FOREIGN KEY (`course_id`) REFERENCES `course` (`cid`), CONSTRAINT `fk_score_student` FOREIGN KEY (`student_id`) REFERENCES `student` (`sid`) ) ENGINE=InnoDB AUTO_INCREMENT=53 DEFAULT CHARSET=utf8; -- ----------------------------
-- Records of `score` -- ---------------------------- BEGIN; INSERT INTO `score` VALUES ('1', '1', '1', '10'), ('2', '1', '2', '9'), ('5', '1', '4', '66'), ('6', '2', '1', '8'), ('8', '2', '3', '68'), ('9', '2', '4', '99'), ('10', '3', '1', '77'), ('11', '3', '2', '66'), ('12', '3', '3', '87'), ('13', '3', '4', '99'), ('14', '4', '1', '79'), ('15', '4', '2', '11'), ('16', '4', '3', '67'), ('17', '4', '4', '100'), ('18', '5', '1', '79'), ('19', '5', '2', '11'), ('20', '5', '3', '67'), ('21', '5', '4', '100'), ('22', '6', '1', '9'), ('23', '6', '2', '100'), ('24', '6', '3', '67'), ('25', '6', '4', '100'), ('26', '7', '1', '9'), ('27', '7', '2', '100'), ('28', '7', '3', '67'), ('29', '7', '4', '88'), ('30', '8', '1', '9'), ('31', '8', '2', '100'), ('32', '8', '3', '67'), ('33', '8', '4', '88'), ('34', '9', '1', '91'), ('35', '9', '2', '88'), ('36', '9', '3', '67'), ('37', '9', '4', '22'), ('38', '10', '1', '90'), ('39', '10', '2', '77'), ('40', '10', '3', '43'), ('41', '10', '4', '87'), ('42', '11', '1', '90'), ('43', '11', '2', '77'), ('44', '11', '3', '43'), ('45', '11', '4', '87'), ('46', '12', '1', '90'), ('47', '12', '2', '77'), ('48', '12', '3', '43'), ('49', '12', '4', '87'), ('52', '13', '3', '87'); COMMIT; -- ----------------------------
--  Table structure for `student` -- ---------------------------- DROP TABLE IF EXISTS `student`; CREATE TABLE `student` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `gender` char(1) NOT NULL, `class_id` int(11) NOT NULL, `sname` varchar(32) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_class` (`class_id`), CONSTRAINT `fk_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`) ) ENGINE=InnoDB AUTO_INCREMENT=17 DEFAULT CHARSET=utf8; -- ----------------------------
-- Records of `student` -- ---------------------------- BEGIN; INSERT INTO `student` VALUES ('1', '男', '1', '理解'), ('2', '女', '1', '钢蛋'), ('3', '男', '1', '张三'), ('4', '男', '1', '张一'), ('5', '女', '1', '张二'), ('6', '男', '1', '张四'), ('7', '女', '2', '铁锤'), ('8', '男', '2', '李三'), ('9', '男', '2', '李一'), ('10', '女', '2', '李二'), ('11', '男', '2', '李四'), ('12', '女', '3', '如花'), ('13', '男', '3', '刘三'), ('14', '男', '3', '刘一'), ('15', '女', '3', '刘二'), ('16', '男', '3', '刘四'); COMMIT; -- ----------------------------
--  Table structure for `teacher` -- ---------------------------- DROP TABLE IF EXISTS `teacher`; CREATE TABLE `teacher` ( `tid` int(11) NOT NULL AUTO_INCREMENT, `tname` varchar(32) NOT NULL, PRIMARY KEY (`tid`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8; -- ----------------------------
-- Records of `teacher` -- ---------------------------- BEGIN; INSERT INTO `teacher` VALUES ('1', '张磊老师'), ('2', '李平老师'), ('3', '刘海燕老师'), ('4', '朱云海老师'), ('5', '李杰老师'); COMMIT; SET FOREIGN_KEY_CHECKS = 1;

示例代码

SQL练习题数据库

　　1、查询全部的课程的名称以及对应的任课老师姓名 　　4、查询平均成绩大于八十分的同窗的姓名和平均成绩 　　7、 查询没有报李平老师课的学生姓名 　　8、 查询没有同时选修物理课程和体育课程的学生姓名 　　九、 查询挂科超过两门(包括两门)的学生姓名和班级

# 参考答案 #一、查询全部的课程的名称以及对应的任课老师姓名
SELECT course.cname, teacher.tname FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid;  #四、查询平均成绩大于八十分的同窗的姓名和平均成绩
SELECT student.sname, t1.avg_num FROM student INNER JOIN ( SELECT student_id, avg(num) AS avg_num FROM score GROUP BY student_id HAVING avg(num) > 80 ) AS t1 ON student.sid = t1.student_id;  #七、 查询没有报李平老师课的学生姓名(找出报名李平老师课程的学生，而后取反就能够)
SELECT student.sname FROM student WHERE sid NOT IN ( SELECT DISTINCT student_id FROM score WHERE course_id IN ( SELECT course.cid FROM course INNER JOIN teacher ON course.teacher_id = teacher.tid WHERE teacher.tname = '李平老师' ) );  #八、 查询没有同时选修物理课程和体育课程的学生姓名(没有同时选修指的是选修了一门的，
思路是获得物理+体育课程的学生信息表，而后基于学生分组，统计count(课程)=1) SELECT student.sname FROM student WHERE sid IN ( SELECT student_id FROM score WHERE course_id IN ( SELECT cid FROM course WHERE cname = '物理' OR cname = '体育' ) GROUP BY student_id HAVING COUNT(course_id) = 1 );  # 九、 查询挂科超过两门(包括两门)的学生姓名和班级
select student.sname,class.caption from class INNER JOIN student on class.cid = student.class_id WHERE student.sid in (select student_id from score where num < 60 GROUP BY student_id HAVING COUNT(course_id) >=2) ;

参考答案

pymysql模块　ide

　　一、安装pymysql模块测试

　　terminal下执行： 　　pip3 install pymysql

　　二、代码链接fetch

import pymysql # 连接
conn=pymysql.connect( host='localhost', user='root', password='123', database='egon', charset='utf8') # 游标
cursor=conn.cursor() # 执行完毕返回的结果集默认以元组显示 #cursor=conn.cursor(cursor=pymysql.cursors.DictCursor) # 以字典的方式显示数据

View Code

　　三、pymysql操做数据库spa

# 执行sql语句
user = input(">>>:").strip() pwd = input(">>>:").strip() sql='select * from userinfo where name="%s" and password="%s"' %(user,pwd) # 注意%s须要加引号
 rows=cursor.execute(sql) # 执行sql语句，返回sql查询成功的记录数目 # 获取真实数据cursor.fetchone(),cursor.fetchall(),cursor.fetchmany(), # 相似管道取值，获取一条，全部，多条
 cursor.scroll(1,'relative')  # 相对移动
cursor.scroll(3,'absolute')  # 绝对移动
cursor.close() conn.close()

View Code

SQL注入问题设计

username = input(">>>:").strip() password = input(">>>:").strip() sql = "select * from user where username='%s' and password='%s'"%(username,password) # 不要手动去拼接查询的sql语句，要经过excute去传参
 # 用户名正确的状况
username >>>: jason' -- jjsakfjjdkjjkjs
 # 用户名密码都不对的状况
username >>>: xxx' or 1=1 --asdjkdklqwjdjkjasdljad
password >>>: '' 如何解决注入问题： 经过cursor.excute(sql,('jason', '123'))作处理

经过pymysql模块增删改查 MySQLcode

# 增
sql = "insert into user(username,password) values(%s,%s)" rows = cursor.excute(sql,('jason','123'))  # 一次插入多行记录
res = cursor,excutemany(sql,[(),(),()]  # 修改
sql = "update user set username='jasonDSB' where id=1" rows = cursor.excute(sql) """ 增和改单单执行excute并不会真正影响到数据，
须要再执行conn.commit()才能够完成真正的增改 """  # 删
sql = "delete name from user shere id = 1" rows = cursor.excute(sql)