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Given a char array representing tasks CPU need to do. It contains capital letters A to Z where different letters represent different tasks. Tasks could be done without original order. Each task could be done in one interval. For each interval, CPU could finish one task or just be idle.git
However, there is a non-negative cooling interval n that means between two same tasks, there must be at least n intervals that CPU are doing different tasks or just be idle.github
You need to return the least number of intervals the CPU will take to finish all the given tasks. api
Example:数组
Input: tasks = ["A","A","A","B","B","B"], n = 2 Output: 8 Explanation: A -> B -> idle -> A -> B -> idle -> A -> B.
Note:微信
给定一个用字符数组表示的 CPU 须要执行的任务列表。其中包含使用大写的 A - Z 字母表示的26 种不一样种类的任务。任务能够以任意顺序执行,而且每一个任务均可以在 1 个单位时间内执行完。CPU 在任何一个单位时间内均可以执行一个任务,或者在待命状态。spa
然而,两个相同种类的任务之间必须有长度为 n 的冷却时间,所以至少有连续 n 个单位时间内 CPU 在执行不一样的任务,或者在待命状态。rest
你须要计算完成全部任务所须要的最短期。code
示例 1:htm
输入: tasks = ["A","A","A","B","B","B"], n = 2 输出: 8 执行顺序: A -> B -> (待命) -> A -> B -> (待命) -> A -> B.
注:
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 var cnt:[Int] = [Int](repeating:0,count:26) 4 for task in tasks 5 { 6 //A:65 7 cnt[task.ascii - 65] += 1 8 } 9 cnt.sort() 10 var i:Int = 25 11 var mx:Int = cnt[25] 12 var len:Int = tasks.count 13 while (i >= 0 && cnt[i] == mx) 14 { 15 i -= 1 16 } 17 return max(len, (mx - 1) * (n + 1) + 25 - i) 18 } 19 } 20 21 //Character扩展 22 extension Character 23 { 24 //转ASCII整数值(定义小写为整数值) 25 var ascii: Int { 26 get { 27 return Int(self.unicodeScalars.first!.value) 28 } 29 } 30 }
1118ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 guard !tasks.isEmpty else {return 0} 4 var map = [Int](repeating: 0, count: 26) 5 let taskStr = String(tasks) 6 let offset = "A".utf8.first! 7 for task in taskStr.utf8{ 8 let count = Int(task - offset) 9 map[count] += 1 10 } 11 var mostFrequency = 0 12 var numOfMostFrequency = 0 13 for count in map { 14 if count == mostFrequency { 15 numOfMostFrequency += 1 16 } else if count > mostFrequency { 17 mostFrequency = count 18 numOfMostFrequency = 1 19 } 20 } 21 22 return max((n+1) * (mostFrequency-1) + numOfMostFrequency, tasks.count) 23 } 24 }
1208ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 guard n > 0 else { return tasks.count } 4 5 var items = Array<Int>(repeating: 0, count: 26) 6 let aValue = Int(UnicodeScalar("A").value) 7 tasks.forEach { (char) in 8 items[Int(UnicodeScalar(String(char))!.value) - aValue] += 1 9 } 10 11 items.sort() 12 var maxCount = items[25] - 1 13 var maxIdleTimes = (items[25] - 1) * n 14 15 for i in 1..<items.count { 16 guard items[25 - i] > 0 else { continue } 17 maxIdleTimes -= min(maxCount, items[25 - i]) 18 } 19 20 return maxIdleTimes < 0 ? tasks.count : tasks.count + maxIdleTimes 21 } 22 }
1224ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 var counter = [Character: Int]() 4 tasks.forEach{ counter[$0, default: 0] += 1 } 5 let m = counter.values.max()! 6 let numMax = counter.values.filter{ $0 == m }.count 7 let slots = (m - 1) * (n + 1) 8 return numMax + max(slots, tasks.count - numMax) 9 } 10 }
1240ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 var counts = [Character:Int]() 4 for task in tasks { 5 counts[task, default: 0] += 1 6 } 7 var keys = counts.keys.sorted { 8 return counts[$0]! > counts[$1]! 9 } 10 let maxCount = counts[keys.first!]! 11 keys.removeFirst() 12 var idleSlots = (maxCount - 1) * n 13 for char in keys { 14 idleSlots -= min(maxCount - 1, counts[char]!) 15 idleSlots = max(idleSlots, 0) 16 } 17 return idleSlots + tasks.count 18 } 19 }
1252ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 let totalTask = tasks.count 4 guard totalTask > 0 else { return 0 } 5 guard n > 0 else { return totalTask } 6 var taskCount: [Character: Int] = [:] 7 var biggestTaskCount = 1 8 for task in tasks { 9 if let count = taskCount[task] { 10 taskCount[task] = count + 1 11 if biggestTaskCount < count + 1 { 12 biggestTaskCount = count + 1 13 } 14 }else { 15 taskCount[task] = 1 16 } 17 } 18 19 if (biggestTaskCount * (n + 1)) <= tasks.count { 20 return tasks.count 21 } 22 23 24 var total = (biggestTaskCount - 1) * (n + 1) 25 26 for (_, value) in taskCount { 27 if value == biggestTaskCount { 28 total += 1 29 } 30 } 31 32 return total 33 } 34 }
1256ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 var map = [Character: Int]() 4 var maxCount = 0 5 for task in tasks { 6 if let val = map[task] { 7 map[task] = val + 1 8 maxCount = max(maxCount, val + 1) 9 } else { 10 maxCount = max(maxCount, 1) 11 map[task] = 1 12 } 13 } 14 15 let sortedMap = map.sorted { $0.1 > $1.1 } 16 maxCount -= 1 17 var idlesAmount = maxCount * n 18 var charCount = maxCount 19 for i in 1..<sortedMap.count { 20 let (key, val) = sortedMap[i] 21 idlesAmount -= min(val, maxCount) 22 } 23 24 return idlesAmount > 0 ? tasks.count + idlesAmount : tasks.count 25 } 26 }
1260ms
1 class Solution { 2 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 3 var countMap: [Character: Int] = [:] 4 for task in tasks { 5 countMap[task] = (countMap[task] ?? 0) + 1 6 } 7 let maxCount: Int = countMap.values.max() ?? 0 8 let fullPeriodCount = maxCount - 1 9 var maxIdles = fullPeriodCount * (n + 1) 10 for count in countMap.values { 11 maxIdles -= min(fullPeriodCount, count) 12 } 13 return tasks.count + max(0, maxIdles) 14 } 15 }
1264ms
1 class Solution { 2 func isValid(_ intervals: Int, _ table: [Character: Int], _ len: Int, _ maxCount: Int, _ maxCountTies: Int) -> Bool { 3 let rest = intervals%len 4 var rounds = intervals/len + (rest == 0 ? 0 : 1) 5 if rounds < maxCount || (rounds == maxCount && 0 < rest && rest < maxCountTies) { 6 return false 7 } 8 9 return true 10 } 11 12 func binarySearch(_ low: Int, _ high: Int, _ table: [Character : Int], _ n: Int, _ maxCount: Int, _ maxCountTies: Int) -> Int { 13 if low == high { 14 return low 15 } 16 17 let mid = (low+high)/2 18 if isValid(mid, table, n, maxCount, maxCountTies) == true { 19 return binarySearch(low, mid, table, n, maxCount, maxCountTies) 20 } else { 21 return binarySearch(mid+1, high, table, n, maxCount, maxCountTies) 22 } 23 24 } 25 26 func leastInterval(_ tasks: [Character], _ n: Int) -> Int { 27 if tasks.count == 0 { 28 return 0 29 } 30 31 if n == 0 { 32 return tasks.count 33 } 34 35 var table: [Character: Int] = [:] 36 for ch in tasks { 37 table[ch] = (table[ch] ?? 0) + 1 38 } 39 40 var maxCount = table.values.reduce(0, {max($0, $1)}) 41 var maxCountTies = table.values.reduce(0, {$0 + ($1 == maxCount ? 1 : 0)}) 42 43 let tasksCount = tasks.count 44 let low = max(tasksCount, (maxCount-1)*(n+1)+1) 45 let high = tasksCount*(n+1) 46 47 return binarySearch(low, high, table, n+1, maxCount, maxCountTies) 48 } 49 }