练习题

一个字符串里面aAd123sdacD12dad2，而后遇到数字取第一个，后面的数字用来分隔，结果是这样
【aAd1，sdacD1，dad2】

import string

ss = 'aaa123bbb321cc456'
flag = 1
str_temp = ''
a = []
for i in ss:
    if i.isalpha():
        str_temp += i
        flag = 1
    elif i.isdigit():
        if flag == 1:
            str_temp += i
            a.append(str_temp)
            flag = 0
            str_temp = ''
print(a)
f.close()

['aaa1', 'bbb3', 'cc4']

s = 'aaa123bb234cc345'
res = []
t = ''

for i in s:
    t += i
    if i.isdigit():
        if not t.isdigit():
            res.append(t)
        t = ''
print(res)

 

import re

ss = '22aaa123bbb321cc456'

temp = re.findall(pattern='\D+\d', string=ss)
print(temp)

 

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查找文件中以print开头的行的内容及行号
import re
count = 1
d = {}
f = open("C:/Users/asus/Desktop/1.py",'r')
tmp = f.readline()
if tmp == '':
    d[count] = tmp
# pattern = re.compile(r"^print")

while tmp:
    str = re.findall(pattern='^print', string=tmp, flags=re.I)
    if len(str) != 0:
        # sb = "%d:%s" % (count, tmp)
        d[count] = tmp
    count += 1
    tmp = f.readline()
print(d)