MySQL中字符串和数字拼接

select * from qa_employ where EMPLOY_GROUP =2

原先雇佣表中全部雇佣姓名所有是"张三"，

但愿将雇用姓名变得不同，好比张三+id

SQLserver中直接用

 

update   qa_employ
set EMPLOY_NAME = EMPLOY_NAME+EMPLOY_id
where EMPLOY_ID > 10

即便发现EMPLOY_id是int类型，最多用cast转一下

 

update   qa_employ
set EMPLOY_NAME = EMPLOY_NAME+cast （EMPLOY_id as char）
where EMPLOY_ID > 10

但在mySQL报错

 1292 - Truncated incorrect DOUBLE value

 

update qa_employ
set EMPLOY_NAME = concat("开发人员",EMPLOY_id)
where EMPLOY_ID > 10

 

update qa_employ set EMPLOY_NAME = concat("开发人员",EMPLOY_id) where EMPLOY_ID > 10 

UPDATE QA_BUGLIST SET BUG_TASK_NUM = CASE (BUG_ID %13) WHEN 0 THEN 'TASK#201913' ELSE CONCAT('TASK#1110',BUG_ID %13) END