Golang中Buffer高效拼接字符串以及自定义线程安全Buffer

本文原创文章,转载注明出处,博客地址 https://segmentfault.com/u/to... 第一时间看后续精彩文章。以为好的话,顺手分享到朋友圈吧,感谢支持。bootstrap

Go中可使用“+”合并字符串,可是这种合并方式效率很是低,每合并一次,都是建立一个新的字符串,就必须遍历复制一次字符串。Java中提供StringBuilder类(最高效,线程不安全)来解决这个问题。Go中也有相似的机制,那就是Buffer(线程不安全)。segmentfault

如下是示例代码:
package main

import (
    "bytes"
    "fmt"
)

func main() {
    var buffer bytes.Buffer
    for i := 0; i < 1000; i++ {
        buffer.WriteString("a")
    }
    fmt.Println(buffer.String())
}

使用bytes.Buffer来组装字符串,不须要复制,只须要将添加的字符串放在缓存末尾便可。缓存

Buffer为何线程不安全?

The Go documentation follows a simple rule: If it is not explicitly stated that concurrent access to something is safe, it is not.安全

==Go文档遵循一个简单的规则:若是没有明确声明并发访问某事物是安全的,则不是。==并发

如下是Golang中bytes.Buffer部分源码
// A Buffer is a variable-sized buffer of bytes with Read and Write methods.
// The zero value for Buffer is an empty buffer ready to use.
type Buffer struct {
    buf       []byte   // contents are the bytes buf[off : len(buf)]
    off       int      // read at &buf[off], write at &buf[len(buf)]
    bootstrap [64]byte // memory to hold first slice; helps small buffers avoid allocation.
    lastRead  readOp   // last read operation, so that Unread* can work correctly.
}

// Write appends the contents of p to the buffer, growing the buffer as
// needed. The return value n is the length of p; err is always nil. If the
// buffer becomes too large, Write will panic with ErrTooLarge.
func (b *Buffer) Write(p []byte) (n int, err error) {
    b.lastRead = opInvalid
    m := b.grow(len(p))
    return copy(b.buf[m:], p), nil
}

// Read reads the next len(p) bytes from the buffer or until the buffer
// is drained. The return value n is the number of bytes read. If the
// buffer has no data to return, err is io.EOF (unless len(p) is zero);
// otherwise it is nil.
func (b *Buffer) Read(p []byte) (n int, err error) {
    b.lastRead = opInvalid
    if b.off >= len(b.buf) {
        // Buffer is empty, reset to recover space.
        b.Truncate(0)
        if len(p) == 0 {
            return
        }
        return 0, io.EOF
    }
    n = copy(p, b.buf[b.off:])
    b.off += n
    if n > 0 {
        b.lastRead = opRead
    }
    return
}

源码对于Buffer的定义中,并无关于锁的字段,在write和read函数中也未发现锁的踪迹,因此符合上面提到的文档中的rule,即Buffer并发是不安全的app

如何自定义实现一个并发安全的Buffer

type Buffer struct {
    b bytes.Buffer
    rw sync.RWMutex
}
func (b *Buffer) Read(p []byte) (n int, err error) {
    b.rw.RLock()
    defer b.rw.RUnlock()
    return b.b.Read(p)
}
func (b *Buffer) Write(p []byte) (n int, err error) {
    b.rw.Lock()
    defer b.rw.Unlock()
    return b.b.Write(p)
}

经过读写锁,解决并发读写问题,以上提供了Read和Write函数,亲,是否是Golang代码简洁明了?其它函数能够在Golang关于Buffer源码的基础上自行实现less

两种锁的区别
sync.Mutex(互斥锁) sync.RWMutex(读写锁)
当一个goroutine访问的时候,其余goroutine都不能访问,保证了资源的同步,避免了竞争,不过也下降了性能 非写状态时:多个Goroutine能够同时读,一个Goroutine写的时候,其它Goroutine不能读也不能写,性能好
相关文章
相关标签/搜索