CF1313 C2. Skyscrapers (hard version)
C2. Skyscrapers (hard version) 题意： 求一个新的序列，使得其合最大，要求新的序列知足该序列的最大值左右两边（能够只有一边）呈非升序列。 思路： 单调栈 C1 n小模拟暴力O(n^3)也过了 C2是在C1的基础上优化。 咱们遍历i，默认i为最小值，求左侧的面积（假设宽都为1） 再反向遍历求右侧每一个i对应点的面积 将两个面积加起来-掉i那块的面积(否则的话会算两个i那
相关文章
- 1. Codeforces Round #622 (Div. 2) C2.Skyscrapers (hard version)DP+单调栈
- 2. C2 - Exam in BerSU (hard version)
- 3. C2. Exam in BerSU (hard version)
- 4. CodeForces C2. Exam in BerSU (hard version)
- 5. C2. Exam in BerSU (hard version)（CF 思惟）
- 6. Codeforces Round #555 (Div. 3) C2. Increasing Subsequence (hard version)
- 7. Codeforces Round #568 (Div. 2) C2. Exam in BerSU (hard version)
- 8. Codeforces Round #568 (Div. 2) C2. Exam in BerSU (hard version)
- 9. Codeforces Round #568 (Div. 2)C2. Exam in BerSU (hard version)
- 10. Equalizing by Division (easy version)&&(hard version)
- 更多相关文章...
- • Docker version 命令 - Docker命令大全
- • Hibernate多对多映射关系 - Hibernate教程
- • 为了进字节跳动，我精选了29道Java经典算法题，带详细讲解
- • Java 8 Stream 教程
相关标签/搜索
每日一句
-
每一个你不满意的现在，都有一个你没有努力的曾经。
欢迎关注本站公众号,获取更多信息
相关文章
- 1. Codeforces Round #622 (Div. 2) C2.Skyscrapers (hard version)DP+单调栈
- 2. C2 - Exam in BerSU (hard version)
- 3. C2. Exam in BerSU (hard version)
- 4. CodeForces C2. Exam in BerSU (hard version)
- 5. C2. Exam in BerSU (hard version)（CF 思惟）
- 6. Codeforces Round #555 (Div. 3) C2. Increasing Subsequence (hard version)
- 7. Codeforces Round #568 (Div. 2) C2. Exam in BerSU (hard version)
- 8. Codeforces Round #568 (Div. 2) C2. Exam in BerSU (hard version)
- 9. Codeforces Round #568 (Div. 2)C2. Exam in BerSU (hard version)
- 10. Equalizing by Division (easy version)&&(hard version)