Given a list of non negative integers, arrange them such that they form the largest number.code
For example, given [3, 30, 34, 5, 9], the largest formed number is 9534330.orm
Note: The result may be very large, so you need to return a string instead of an integer.utf-8
这有一种很简单的思路:
咱们无非是要判断哪一个串放在哪一个的前面或者后面,这其实就是两个数的比较问题,只不过大小的比较方式不是一般的形式。固然经过字符串的处理有不少的方式,不过都略显复杂了,反正两个数的比较就两种状况,因此咱们不妨列拿出来比较下得出结果就行。字符串
#coding=utf-8 class Solution: def cmp(self,x,y): if x*(10**len(str(y)))+y < y*(10**len(str(x)))+x: return 1 elif x*(10**len(str(y)))+y == y*(10**len(str(x)))+x: return 0 else: return -1 # @param num, a list of integers # @return a string def largestNumber(self, num): num.sort(self.cmp) return str(int(''.join(map(lambda x: str(x),num))))