0832. Flipping an Image (E)

时间 2020-11-16

标签 java code class sed 遍历 ping 栏目 Java 繁體版

原文原文链接

Flipping an Image (E)

题目

Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.java

To flip an image horizontally means that each row of the image is reversed. For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].code

To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].ip

Example 1:it

Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]

Example 2:io

Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]

Notes:class

1 <= A.length = A[0].length <= 20
0 <= A[i][j] <= 1

题意

将矩阵中每一行逆序，并将矩阵中的1和0互换。sed

思路

直接遍历处理便可。遍历

代码实现

Java

class Solution {
    public int[][] flipAndInvertImage(int[][] A) {
        for (int[] arr : A) {
            int i = 0, j = arr.length - 1;
            while (i < j) {
                if (arr[i] == arr[j]) {
                    arr[i] = 1 - arr[i];
                    arr[j] = 1 - arr[j];
                }
                i++;
                j--;
            }
            if (i == j) {
                arr[i] = 1 - arr[i];
            }
        }
        return A;
    }
}