这周的主要任务:userInfo页面Modify逻辑bug修复,search功能逻辑实现。html
(一)Modify逻辑bug修复:session
这里存在的bug就是在咱们不重置password的时候依照前面的逻辑是不能提交改动,这个逻辑是错误的,应该改成可以不改动password也能提交,主要是if逻辑推断的改动spa
先看一下代码:设计
def userInfo(request, user_id): try: user = User.objects.get(userID = request.session['userID']) except: return HttpResponseRedirect("/index/login") other = User.objects.get(userID = user_id) if request.method == 'POST': if request.POST.has_key("Modify"): userID = request.session['userID'] oldPassword = request.POST['oldPassword'] password = request.POST['password'] confirmPassword = request.POST['confirmPassword'] session = request.POST['session'] specialty = request.POST['specialty'] tel = request.POST['tel'] email = request.POST['email'] nickname = request.POST['nickname'] if oldPassword != user.password: return HttpResponse("password error") else: user.password = oldPassword user.session = session user.specialty = specialty user.tel = tel user.email = email user.nickname = nickname if password.strip() != '' and password == confirmPassword: user.password = password user.save() other = User.objects.get(userID = user_id) return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'],'user': user, 'other':other}) else: if password != confirmPassword: return HttpResponse("password and confirmPassword is not the same!") else: user.save() other = User.objects.get(userID = user_id) return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'], 'user':user, 'other':other}) else: users = User.objects.all() userid = request.POST['idname'] try: if userid.strip(): users = users.filter(userID__contains = userid) #return HttpResponse(users return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'], 'user': user, 'other':other, 'users':users, 'idname':userid }) except : #return HttpResponse("fuck") return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'],'user': user, 'other':other, 'users':{} }) else: return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'],'user': user, 'other':other, 'users':{} })
哪个的提交呢。在网上查了一下,一种解决方法就是给不一样的submit标记不一样的name,而后再假设request.POST.has_key("Modify")成立就表明提交的是Modifybutton,不然的code
话就是Search的提交了。这样的方法仍是比較有用的。htm
对于上述的Modify的逻辑的问题,主要就是先推断假设password和confirmpassword一样且不空的时候,提交改动。在推断二者不一样样的时候错误提示。在推断二者同为对象
空的时候提交改动。这样就符合实际的状况了。blog
(二):UserInfo页面搜索实现:ip
依照上周的估计,是要在UserInfo页面实现一个用户的搜索,事实上原理和problemList的搜索差点儿相同。当咱们攻克了一个表单中有多个button的时候,那么就是一个逻辑推断而已。ci
if request.POST,has_key("Modify") else 运行搜索的过程:
users = User.objects.all() userid = request.POST['idname'] Nickname = request.POST['idname'] try: if userid.strip(): users = users.filter(userID__contains = userid) #return HttpResponse(users) return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'], 'user': user, 'other':other, 'users':users, 'idname':userid }) except : #return HttpResponse("fuck") return render(request, 'cugbacm/userInfo.html', {'userID':request.session['userID'],'user': user, 'other':other, 'users':{} })
当咱们推断是来自Search的请求时,首先使用request.POST["idname"]从页面取出来输入的查询条件。而后初始化user对象集合,而后使用模糊查询(属性名__contains = 查询
条件),注意这里的下划线是两个下划线组成的。而后当咱们得到符合查询要求的集合后就传回到页面。再在页面展现:
<div class = "table-responsive" style = "padding-top:58px"> <table cellpadding = "10" cellspacing = "0" class = "display" id = "example"> <thead> <tr> <th>UserId</th> <th>Username</th> </tr> </thead> <tbody> {%for u in users %} <tr class="odd gradeX"> <td> <a href = "/index/userInfo/{{u.userID}}">{{u.userID}} </a> </td> <td>{{u.nickname}} </td> </tr> {% endfor %} </tbody> </table> </div>
这里生成了一个Table存放查出来的结果,而后一个{% for u in users %}循环展式查询到的结果。就会生成一个表。而后现在的设计是点击某一个展现项的,调到userInfo页
面,只是没有了查询结果而已。
而后这周基本的任务也就这么点代码而已。这周进度有点慢.......。但愿后面的任务能够遇上去。