问题:算法
Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.数组
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.cookie
Example 1:spa
Input: [1,2,3], [1,1] //第一个是知足值,第二个是cookie数目 Output: 1 Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content. You need to output 1.
Example 2:指针
Input: [1,2], [1,2,3] Output: 2 Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. You have 3 cookies and their sizes are big enough to gratify all of the children, You need to output 2.
解决:排序
① 典型的贪心算法,给定一堆cookie,每一个cookie的大小不一样,还有一堆小朋友,每一个小朋友的胃口也不一样的,问咱们当前的cookie最多能知足几个小朋友。it
一、首先把两个数组排序io
二、若是当前饼干大小小于知足感,指针前移,不然两个指针都前移。cookies
三、最后返回指向孩子指针的指针位置class
class Solution { //18ms public int findContentChildren(int[] g, int[] s) { Arrays.sort(g); Arrays.sort(s); int p1 = 0; int p2 = 0; while(p1 < g.length && p2 < s.length){ if(g[p1] <= s[p2]) p1 ++; p2 ++; } return p1; } }