leetcode-455-Assign Cookies

题目描述：

Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

Note:
You may assume the greed factor is always positive. 
You cannot assign more than one cookie to one child.

Example 1:

Input: [1,2,3], [1,1]

Output: 1

Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.

 

Example 2:

Input: [1,2], [1,2,3]

Output: 2

Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
You have 3 cookies and their sizes are big enough to gratify all of the children, 
You need to output 2.

要完成的函数：

int findContentChildren(vector<int>& g, vector<int>& s)

 

说明：

一、这道题目看清题意就不难了。每一个孩子有个需求尺寸数，是整数，一、二、3这样子的。有几块饼干，尺寸是整数，一、二、3这样子的。不能把饼干掰开给。

要求输出可以知足几个孩子的需求。

二、首先对需求尺寸数g进行排序，对饼干尺寸数s进行排序，而后从g和s的第一位开始比较，直到g或者s处理完了。

代码也很简单，以下：

    int findContentChildren(vector<int>& g, vector<int>& s) { sort(g.begin(),g.end()); sort(s.begin(),s.end()); int i=0,j=0; while(i<g.size()&&j<s.size())//处理完全部孩子的需求或者已经没有知足需求的饼干了
 { if(s[j]>=g[i]) i++; //若是知足了处理下一个i
            j++;//若是不知足j一直加
 } return i; }

上述代码实测40ms，beats 97.41% of cpp submissions。