Codeforces Round #687 (Div. 2) 题解

题目连接：Codeforces Round #687 (Div. 2) A. Prison Break 找四个角到(r,c)的最大距离便可html int main() { int t; cin >> t; while(t--) { int n,m,r,c; cin >> n >> m >> r >> c; int ans=0; ans=max(an

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