Educational Codeforces Round 61 (Rated for Div. 2)(题解)

Educational Codeforces Round 61 (Rated for Div. 2)(题解) A. Regular Bracket Sequence 题目大意 给出一些括号串"((","()",")(","))" ,cnt1,cnt2,cnt3,cnt4个，问用这些括号串可否组成括号之间相互匹配的大括号串html 解题思路 只要“((”,"))“的数目相等，且在其都为0时不存在”)

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