[Swift]LeetCode1020. 飞地的数量 | Number of Enclaves

时间 2019-11-11

标签 swift leetcode1020 leetcode 飞地数量 number enclaves 栏目 Swift 繁體版

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Given a 2D array A, each cell is 0 (representing sea) or 1 (representing land)git

A move consists of walking from one land square 4-directionally to another land square, or off the boundary of the grid.github

Return the number of land squares in the grid for which we cannot walk off the boundary of the grid in any number of moves. 数组

Example 1:微信

Input: [[0,0,0,0],[1,0,1,0],[0,1,1,0],[0,0,0,0]]
Output: 3 Explanation: There are three 1s that are enclosed by 0s, and one 1 that isn't enclosed because its on the boundary.

Example 2:app

Input: [[0,1,1,0],[0,0,1,0],[0,0,1,0],[0,0,0,0]]
Output: 0 Explanation: All 1s are either on the boundary or can reach the boundary.

Note:spa

1 <= A.length <= 500
1 <= A[i].length <= 500
0 <= A[i][j] <= 1
All rows have the same size.

给出一个二维数组 A，每一个单元格为 0（表明海）或 1（表明陆地）。code

移动是指在陆地上从一个地方走到另外一个地方（朝四个方向之一）或离开网格的边界。htm

返回网格中没法在任意次数的移动中离开网格边界的陆地单元格的数量。 blog

示例 1：

输入：[[0,0,0,0],[1,0,1,0],[0,1,1,0],[0,0,0,0]]
输出：3
解释： 
有三个 1 被 0 包围。一个 1 没有被包围，由于它在边界上。

示例 2：

输入：[[0,1,1,0],[0,0,1,0],[0,0,1,0],[0,0,0,0]]
输出：0
解释：
全部 1 都在边界上或能够到达边界。

提示：

1 <= A.length <= 500
1 <= A[i].length <= 500
0 <= A[i][j] <= 1
全部行的大小都相同

432ms

 1 class Solution {
 2     func numEnclaves(_ A: [[Int]]) -> Int {
 3         var grid = A
 4         for row in 0..<grid.count {
 5             dfs(&grid, row, 0)
 6             dfs(&grid, row, grid[0].count - 1)
 7         }
 8         
 9         if grid.count > 0 && grid[0].count > 0 {
10             for col in 0..<grid[0].count {
11                 dfs(&grid, 0, col)
12                 dfs(&grid, grid.count - 1, col)
13             }
14         }
15         
16         var result = 0
17         for row in 0..<grid.count {
18             for col in 0..<grid[0].count {
19                 result += grid[row][col]
20             }
21         }
22         return result
23     }
24     
25     func dfs(_ grid: inout [[Int]], _ row: Int, _ col: Int) {
26         if grid.count == 0 || grid[0].count == 0 {
27             return 
28         }
29         if row < 0 || row > grid.count - 1 
30             || col < 0 || col > grid[0].count - 1 {
31             return 
32         }
33         
34         if grid[row][col] == 0 {
35             return
36         }
37         
38         grid[row][col] = 0
39         
40         dfs(&grid, row + 1, col);
41         dfs(&grid, row - 1, col);
42         dfs(&grid, row, col + 1);
43         dfs(&grid, row, col - 1);
44     }
45 }

444ms

 1 class Solution {
 2     func numEnclaves(_ A: [[Int]]) -> Int {
 3         guard A.count > 0 else { return 0 }
 4         guard A[0].count > 0 else { return 0 }
 5         
 6         let h = A.count
 7         let w = A[0].count
 8         
 9         var visited = Array(repeating: Array(repeating: false, count: w), count: h)
10         var queue = [(Int, Int)]()
11         for i in 0..<h {
12             if A[i][0] == 1 {
13                 queue.append((i, 0))
14                 visited[i][0] = true
15             }
16             
17             if w != 1 && A[i][w - 1] == 1 {
18                 queue.append((i, w - 1))
19                 visited[i][w - 1] = true
20             }
21         }
22         
23         for j in 0..<w {
24             if A[0][j] == 1 {
25                 queue.append((0, j))
26                 visited[0][j] = true
27             }
28             
29             if h != 1 && A[h - 1][j] == 1 {
30                 queue.append((h - 1, j))
31                 visited[h - 1][j] = true
32             }
33         }
34         
35         while queue.count > 0 {
36             var nextQueue = [(Int, Int)]()
37             for point in queue {
38                 let row = point.0
39                 let col = point.1
40                 
41                 if row - 1 >= 0 && A[row - 1][col] == 1 && !visited[row - 1][col] {
42                     visited[row - 1][col] = true
43                     nextQueue.append((row - 1, col))
44                 }
45                 
46                 if row + 1 < h && A[row + 1][col] == 1 && !visited[row + 1][col] {
47                     visited[row + 1][col] = true
48                     nextQueue.append((row + 1, col))
49                 }
50                 
51                 if col - 1 >= 0 && A[row][col - 1] == 1 && !visited[row][col - 1] {
52                     visited[row][col - 1] = true
53                     nextQueue.append((row, col - 1))
54                 }
55                 
56                 if col + 1 < w && A[row][col + 1] == 1 && !visited[row][col + 1] {
57                     visited[row][col + 1] = true
58                     nextQueue.append((row, col + 1))
59                 }
60             }
61             queue = nextQueue
62         }
63         
64         var count = 0
65         
66         for i in 0..<h {
67             for j in 0..<w {
68                 if A[i][j] == 1 && !visited[i][j] {
69                     count += 1
70                 }
71             }
72         }
73         
74         return count
75     }
76 }

452ms

 1 class Solution {
 2         var sum = 0
 3         var ovSum = 0
 4    
 5     func numEnclaves(_ A: [[Int]]) -> Int {
 6         var a = A
 7         
 8         var rowInd = 0
 9         var colInd = 0
10          print(ovSum, sum)
11         rowInd = 0
12         while rowInd < A.count {
13             defer { rowInd += 1 }
14             colInd = 0
15             while colInd < A[rowInd].count {
16                 defer { colInd += 1 }
17                  if a[rowInd][colInd] == 1 {
18                      ovSum += 1
19                  }
20               }
21         }
22         
23          for i in (0..<A.count) {
24             if a[i][0] == 1 { dfs(&a, i, 0)  }
25             if a[i][A[0].count-1] == 1 { dfs(&a, i, A[0].count-1)}
26             
27         }
28        for i in (0..<A[0].count) {
29             if a[0][i] == 1 { dfs(&a, 0, i) }
30             if a[A.count-1][i] == 1 { dfs(&a, A.count-1, i) }
31             
32         }
33         
34         print(ovSum, sum)
35         return ovSum - sum
36     }
37     
38     func dfs(_ a: inout [[Int]], _ rowInd: Int, _ colInd: Int) {
39         guard rowInd < a.count, colInd < a[0].count, rowInd >= 0, colInd >= 0 else { return }
40                if a[rowInd][colInd] != 1 { return }               
41                 a[rowInd][colInd] = 2; sum += 1               
42                     dfs(&a, rowInd - 1, colInd)
43                     dfs(&a, rowInd + 1, colInd)                  
44                     dfs(&a, rowInd, colInd - 1)
45                     dfs(&a, rowInd, colInd + 1)                       
46     }
47 }

Runtime: 488 ms

Memory Usage: 19.1 MB

 1 class Solution {
 2     var DR:[Int] = [-1, 0, +1, 0]
 3     var DC:[Int] = [0, +1, 0, -1]
 4     var R:Int = 0
 5     var C:Int = 0
 6     var grid:[[Int]] = [[Int]]()
 7     var visited:[[Bool]] = [[Bool]](repeating:[Bool](repeating:false,count:505),count:505)
 8     
 9     func numEnclaves(_ A: [[Int]]) -> Int {
10         grid = A
11         R = grid.count
12         C = grid[0].count
13         
14         for r in 0..<R
15         {
16             for c in 0..<C
17             {
18                 if r == 0 || r == R - 1 || c == 0 || c == C - 1
19                 {
20                     if grid[r][c] == 1 && !visited[r][c]
21                     {
22                         dfs(r, c)
23                     }
24                 }
25             }
26         }
27         var ans:Int = 0
28         for r in 0..<R
29         {
30             for c in 0..<C
31             {
32                 if grid[r][c] == 1 && !visited[r][c]
33                 {
34                     ans += 1
35                 }
36             }
37         }
38         return ans     
39     }
40     
41     func dfs(_ r:Int,_ c:Int)
42     {
43         visited[r][c] = true
44         for dir in 0..<4
45         {
46             var nr:Int = r + DR[dir]
47             var nc:Int = c + DC[dir]
48             if nr >= 0 && nr < R && nc >= 0 && nc < C
49             {
50                 if grid[nr][nc] == 1 && !visited[nr][nc]
51                 {
52                     dfs(nr, nc)
53                 }
54             }
55         }
56     }
57 }

524ms

 1 class Solution 
 2 {
 3     func numEnclaves(_ A: [[Int]]) -> Int 
 4     {
 5         guard A.count > 0  else { return 0 }
 6         
 7         var m = A
 8         var ret = 0
 9         for r in 0..<m.count
10         {
11             for c in 0..<m[r].count
12             {
13                 var temp = 0
14                 self.dfs(r,c, &m, &temp)
15                 if temp != -1 { ret += temp}
16             }
17         }
18         
19         return ret
20     }
21     
22     // checked: -1
23     private func dfs(_ r: Int, _ c: Int, _ m: inout [[Int]], _ count: inout Int)
24     {
25         guard r >= 0, c >= 0, r < m.count, c < m[r].count, m[r][c] != -1 else { return }
26         
27         if m[r][c] == 0 { 
28             m[r][c] = -1
29             return 
30         }
31         
32         if r == 0 || c == 0 || r == m.count - 1 || c == m[r].count - 1 { count = -1 }
33         if count != -1 { count += 1 }
34         m[r][c] = -1
35         // up
36         if r > 0 { self.dfs(r - 1, c, &m, &count) }
37         // down
38         if r < m.count - 1 { self.dfs(r + 1, c, &m, &count) }
39         // left
40         if c > 0 { self.dfs(r, c - 1, &m, &count) }
41         // right
42         if c < m[r].count - 1 { self.dfs(r, c + 1, &m, &count) }
43     }
44 }