英文词干提取有多种方式,在实践中,可能涉及到机器学习数据挖掘等多方面的内容。
这里主要介绍的是易于实现的几种原始算法:算法
Lovins (1968)segmentfault
Porter (1980)app
Porter2 (2000)less
Lovins是最先的实现机器学习
算法涉及以下部件:ide
ending, 词后缀,共有294个,详细列表见最后学习
condition, 词后缀去除条件,每一个ending对应一个condition,共有29个,详细列表见最后优化
transformation, 转换ending的方式,共有35个,详细列表见最后rest
算法分为两部:code
对英文词,根据ending列表,按照ending从长到短扫描,找到第一个符合condition的ending
根据剩下的stem应用transformation,将ending转为恰当的形式
英文词为nationally,按照endling列表,从长到短扫描,首先找到 .09. ationally B
,
对应的规则是B Minimum stem length = 3
,要求去除ending后,剩余的部分长度大于等于3
nationally 去除 ationally 后只剩下 n, 不符合condition
继续扫描ending,找到 .07. ionally A
,对应的规则是 A No restrictions on stem
,没有任何限制。
因而最终选定 ionally
做为ending
英文词nationally的stem是nat, 查找transformation,发现没有符合的transformation,不进行变换直接输出。
好比又一个词sitting,第一步获得stem是sitt, 第二步这里会应用第一条transformation,最终输出sit
.11. alistically B arizability A izationally B .10. antialness A arisations A arizations A entialness A .09. allically C antaneous A antiality A arisation A arization A ationally B ativeness A eableness E entations A entiality A entialize A entiation A ionalness A istically A itousness A izability A izational A .08. ableness A arizable A entation A entially A eousness A ibleness A icalness A ionalism A ionality A ionalize A iousness A izations A lessness A .07. ability A aically A alistic B alities A ariness E aristic A arizing A ateness A atingly A ational B atively A ativism A elihood E encible A entally A entials A entiate A entness A fulness A ibility A icalism A icalist A icality A icalize A ication G icianry A ination A ingness A ionally A isation A ishness A istical A iteness A iveness A ivistic A ivities A ization F izement A oidally A ousness A .06. aceous A acious B action G alness A ancial A ancies A ancing B ariser A arized A arizer A atable A ations B atives A eature Z efully A encies A encing A ential A enting C entist A eously A ialist A iality A ialize A ically A icance A icians A icists A ifully A ionals A ionate D ioning A ionist A iously A istics A izable E lessly A nesses A oidism A .05. acies A acity A aging B aical A alist A alism B ality A alize A allic BB anced B ances B antic C arial A aries A arily A arity B arize A aroid A ately A ating I ation B ative A ators A atory A ature E early Y ehood A eless A elity A ement A enced A ences A eness E ening E ental A ented C ently A fully A ially A icant A ician A icide A icism A icist A icity A idine I iedly A ihood A inate A iness A ingly B inism J inity CC ional A ioned A ished A istic A ities A itous A ively A ivity A izers F izing F oidal A oides A otide A ously A .04. able A ably A ages B ally B ance B ancy B ants B aric A arly K ated I ates A atic B ator A ealy Y edly E eful A eity A ence A ency A ened E enly E eous A hood A ials A ians A ible A ibly A ical A ides L iers A iful A ines M ings N ions B ious A isms B ists A itic H ized F izer F less A lily A ness A ogen A ward A wise A ying B yish A .03. acy A age B aic A als BB ant B ars O ary F ata A ate A eal Y ear Y ely E ene E ent C ery E ese A ful A ial A ian A ics A ide L ied A ier A ies P ily A ine M ing N ion Q ish C ism B ist A ite AA ity A ium A ive A ize F oid A one R ous A .02. ae A al BB ar X as B ed E en F es E ia A ic A is A ly B on S or T um U us V yl R s' A 's A .01. a A e A i A o A s W y B
A No restrictions on stem B Minimum stem length = 3 C Minimum stem length = 4 D Minimum stem length = 5 E Do not remove ending after e F Minimum stem length = 3 and do not remove ending after e G Minimum stem length = 3 and remove ending only after f H Remove ending only after t or ll I Do not remove ending after o or e J Do not remove ending after a or e K Minimum stem length = 3 and remove ending only after l, i or u*e L Do not remove ending after u, x or s, unless s follows o M Do not remove ending after a, c, e or m N Minimum stem length = 4 after s**, elsewhere = 3 O Remove ending only after l or i P Do not remove ending after c Q Minimum stem length = 3 and do not remove ending after l or n R Remove ending only after n or r S Remove ending only after dr or t, unless t follows t T Remove ending only after s or t, unless t follows o U Remove ending only after l, m, n or r V Remove ending only after c W Do not remove ending after s or u X Remove ending only after l, i or u*e Y Remove ending only after in Z Do not remove ending after f AA Remove ending only after d, f, ph, th, l, er, or, es or t BB Minimum stem length = 3 and do not remove ending after met or ryst CC Remove ending only after l
1 remove one of double b, d, g, l, m, n, p, r, s, t 2 iev -> ief 3 uct -> uc 4 umpt -> um 5 rpt -> rb 6 urs -> ur 7 istr -> ister 7a metr -> meter 8 olv -> olut 9 ul -> l except following a, o, i 10 bex -> bic 11 dex -> dic 12 pex -> pic 13 tex -> tic 14 ax -> ac 15 ex -> ec 16 ix -> ic 17 lux -> luc 18 uad -> uas 19 vad -> vas 20 cid -> cis 21 lid -> lis 22 erid -> eris 23 pand -> pans 24 end -> ens except following s 25 ond -> ons 26 lud -> lus 27 rud -> rus 28 her -> hes except following p, t 29 mit -> mis 30 ent -> ens except following m 31 ert -> ers 32 et -> es except following n 33 yt -> ys 34 yz -> ys
元音辅音与常见的定义略有不一样:
元音(Vowel) - A E I O U, 以及辅音后边的Y
辅音(Consonant) - 除了 A E I O U,以及元音后边的Y
连续的元音看做元音组V,连续的辅音看做辅音组C,因而任意一个单词均可以表示成VC交错的形式,例如:
segmentfault -> s/e/gm/e/ntf/au/lt -> CVCVCVC porter -> p/o/rt/e/r -> CVCVC application -> a/ppl/i/c/a/t/io/n -> VCVCVCVC apple -> a/ppl/e -> V/C/V
综合起来,能够表示为 VC 组的形式:$$ C^m[V] $$
其中参数m相似于Lovin中condition的stem长度,用于后续的判断
Porter算法以rule为主,rule的形式为:
(condition) S1 -> S2
condition做用于去除了S1的stem,除了m还有其余特征:
m - 表示VC组的数目
* - 表示任意字符, 和子串,v,d,o配合使用
大写字母 - 表示子串
v - 表示一个元音字符
d - 表示两个同样的辅音
o - 表示cvc, 其中第二个c不能是W,X,Y
S1是词的后缀,S2的变化后的后缀
和Lovin不一样,一个词语通过多个规则的串联处理,输出目标词(Lovin是一次性输出)
例如 hopping, 首先应用规则(*v*) ING ->
, 变为hopp
而后应用规则(*d and not (*L or *S or *Z)) -> single letter
,从hopp变为hop
整个算法是从上往下应用规则,有些规则比较特殊,若是触发了要处理额外的规则
规则不少,因而对规则进行分组(step),这里的分组是为了逻辑上作区分(实际上算法也能够根据分组优化),整个算法就是从头到位执行的,流程以下:
do Step_1a
do Step_1b (若是命中step 2b.2 or step 2b.3, 则作一些额外工做)
do Step_1c
do Step_2
do Step_3
do Step_4
do Step_5a
do Step_5b
每一个Step的详细内容见附录
SSES -> SS IES -> I SS -> SS S ->
(m>0) EED -> EE (*v*) ED -> (*v*) ING -> If the second or third of the rules in Step 1b is successful, the following is done: AT -> ATE BL -> BLE IZ -> IZE (*d and not (*L or *S or *Z)) -> single letter (m=1 and *o) -> E
(*v*) Y -> I
(m>0) ATIONAL -> ATE (m>0) TIONAL -> TION (m>0) ENCI -> ENCE (m>0) ANCI -> ANCE (m>0) IZER -> IZE (m>0) ABLI -> ABLE (m>0) ALLI -> AL (m>0) ENTLI -> ENT (m>0) ELI -> E (m>0) OUSLI -> OUS (m>0) IZATION -> IZE (m>0) ATION -> ATE (m>0) ATOR -> ATE (m>0) ALISM -> AL (m>0) IVENESS -> IVE (m>0) FULNESS -> FUL (m>0) OUSNESS -> OUS (m>0) ALITI -> AL (m>0) IVITI -> IVE (m>0) BILITI -> BLE
(m>0) ICATE -> IC (m>0) ATIVE -> (m>0) ALIZE -> AL (m>0) ICITI -> IC (m>0) ICAL -> IC (m>0) FUL -> (m>0) NESS ->
(m>1) AL -> (m>1) ANCE -> (m>1) ENCE -> (m>1) ER -> (m>1) IC -> (m>1) ABLE -> (m>1) IBLE -> (m>1) ANT -> (m>1) EMENT -> (m>1) MENT -> (m>1) ENT -> (m>1 and (*S or *T)) ION -> (m>1) OU -> (m>1) ISM -> (m>1) ATE -> (m>1) ITI -> (m>1) OUS -> (m>1) IVE -> (m>1) IZE ->
(m>1) E -> (m=1 and not *o) E ->
(m > 1 and *d and *L) -> single letter