Java数组内求两数之间最大容积

leetcode学习

题目连接：https://leetcode-cn.com/problems/container-with-most-water/

初解：

public static int maxArea(int[] height) {
    int max = 0;
    int length = height.length;
    for (int i = 0; i < length; i++) {
        for (int j = length-1; j >i; j--) {
            int temp = (height[i] > height[j] ? height[j] : height[i]) * (j - i);
            max = max > temp ? max : temp;
        }
    }
    return max;
}

利用嵌套循环， 指定下标i从左侧开始右移，下标j从右侧开始左移，每次计算两数之间最大溶剂

优解：

public static int maxArea(int[] height) {
    int max = 0;
    int left = 0;
    int right = height.length - 1;
    while (left < right) {
        int temp = (height[left] > height[right] ? height[right] : height[left]) * (right - left);
        max = max > temp ? max : temp;
        if (height[left] > height[right])
            right--;
        else
            left++;
    }
    return max;
}

从初阶解法进阶而来，一样是定位左右两个端点，左端点小则左端点右移，右端点小则右端点左移，将本来的复杂度从O(2n)下降到O(n)