检测地址可否打开[python]

3.6.2python

import urllib.request  
import time  
  
opener = urllib.request.build_opener()  
opener.addheaders = [('User-agent', 'Mozilla/49.0.2')]  
#这个是你放网址的文件名,改过来就能够了  
# file = open('test.txt')  
# lines = file.readlines()  
aa=['http://www.baidu.com/','http://www.baidu.com']  

# for line in lines:  
#     temp=line.replace('\n','')  
#     aa.append(temp)  
# print(aa)  
  
print('开始检查:')  
for a in aa:  
    tempUrl = a  
    try :  
        opener.open(tempUrl)  
        print(tempUrl+'没问题')  
    except urllib.error.HTTPError:  
        print(tempUrl+'=访问页面出错')  
        time.sleep(2)  
    except urllib.error.URLError:  
        print(tempUrl+'=访问页面出错')  
        time.sleep(2)  
    time.sleep(0.1)  
 app

 

2.6ui

 

#!/usr/bin/python2.6  
# -*- coding: utf-8 -*-  
import urllib2
import timeurl

opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/49.0.2')]
#这个是你放网址的文件名,改过来就能够了  
# file = open('test.txt')  
# lines = file.readlines()  
aa=['http://www.baidu.com.com/','http://www.baidu.com']  

# for line in lines:  
#     temp=line.replace('\n','')  
#     aa.append(temp)  
# print(aa)  utf-8

print('开始检查:')
for a in aa:
    tempUrl = a
    try :
        opener.open(tempUrl)
        print(tempUrl+'没问题')
    except urllib.error.HTTPError:
        print(tempUrl+'=访问页面出错')
        time.sleep(2)
    except urllib.error.URLError:
        print(tempUrl+'=访问页面出错')
        time.sleep(2)
    time.sleep(0.1)
 test

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