最近在作远程接口调用时,须要对数据进行加解密,所以返回的参数统一为如下json格式java
{ "code":0, "msg":"成功", "sign":"abcdefghijkl", "timestamp":1491897441000, "data":{} }
首先,咱们假设传输过程当中的对象实体是json
user.javaide
public class User { private int id; private String name; ...省略get set... @Override public String toString() { return "User [id=" + id + ", name=" + name + "]"; } }
当返回的数据转成对象时,可能存在三种状况:测试
1. User 对象 2. List<User> list 对象 3. Page page
Page.javagoogle
public class Page<T> { private int page; private int size; private int total; private List<T> data; ...省略 get set... @Override public String toString() { return "User [page=" + page + ", size=" + size + ", total=" + total + ", data=" + data + "]"; } }
所以返回data的json可能为如下三种:code
1.对象实体的json json -> User对象
{ "id":1, "name":"eric" }
2.对象实体列表的json json -> List<User> list接口
[ { "id":1, "name":"eric" }, { "id":2, "name":"john" } ]
3.分页的实体json json -> Page<User> pageget
{ "page":1, "size":10, "total":2, "data":[ { "id":1, "name":"eric" }, { "id":2, "name":"john" } ] }
所以咱们须要写一个公共类解决上述转换问题it
GsonUtils.java
public class GsonUtils { private GsonUtils() { } public static <T>T fromJson(String json,Class<T> type){ Gson gson = new Gson(); return gson.fromJson(json,type); } public static <T> List<T> listFromJson(String json){ Gson gson = new Gson(); return gson.fromJson(json, new TypeToken<List<T>>(){}.getType()); } }
测试:
public class Main { public static void main(String[] args) { String json1 = "{\"id\":1,\"name\":\"eric\"}"; String json2 = "[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]"; String json3 = "{\"page\":1,\"size\":10,\"total\":2,\"data\":[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]}"; User user = GsonUtils.fromJson(json1, User.class); List<User> lists = GsonUtils.listFromJson(json2); Page<User> page = GsonUtils.fromJson(json3, Page.class); System.out.println("user:" + user); System.out.println("lists:" + lists); System.out.println("page:" + page); } }
运行后的结果:
user:User [id=1, name=eric] lists:[{id=1.0, name=eric}, {id=2.0, name=john}] page:User [page=1, size=10, total=2, list=[{id=1.0, name=eric}, {id=2.0, name=john}]]
此时已经成功将三种格式的json转化为Object,可是这里有个问题以下:若是咱们用一下方法获取user,就会报错,由于处理Java反射TypeToken泛型运行时类型擦除
User user = lists.get(0);
Exception in thread "main" java.lang.ClassCastException: com.google.gson.internal.LinkedTreeMap cannot be cast to swun.test.entity.User at swun.test.Main.main(Main.java:27)
所以咱们将方法listFromJson修改成
public static <T> List<T> listFromJson(String json,Type type){ Gson gson = new Gson(); return gson.fromJson(json, type); }
在调用的时候,将具体的Type传入
public class Main { public static void main(String[] args) { String json1 = "{\"id\":1,\"name\":\"eric\"}"; String json2 = "[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]"; String json3 = "{\"page\":1,\"size\":10,\"total\":2,\"data\":[{\"id\":1,\"name\":\"eric\"},{\"id\":2,\"name\":\"john\"}]}"; User user = GsonUtils.fromJson(json1, User.class); List<User> lists = GsonUtils.listFromJson(json2,new TypeToken<List<User>>(){}.getType()); Page<User> page = GsonUtils.fromJson(json3, Page.class); System.out.println("user:" + user); System.out.println("lists:" + lists); System.out.println("page:" + page); User user1 = lists.get(0); System.out.println("user1:" + user1); } }
运行结果以下:
user:User [id=1, name=eric] lists:[User [id=1, name=eric], User [id=2, name=john]] page:User [page=1, size=10, total=2, data=[{id=1.0, name=eric}, {id=2.0, name=john}]] user1:User [id=1, name=eric]