MySQL记录操做mysql
MySQL数据操做: DML正则表达式
在MySQL管理软件中,能够经过SQL语句中的DML语言来实现数据的操做,包括sql
1. 插入完整数据(顺序插入) 语法一: INSERT INTO 表名(字段1,字段2,字段3…字段n) VALUES(值1,值2,值3…值n); 语法二: INSERT INTO 表名 VALUES (值1,值2,值3…值n); 2. 指定字段插入数据 语法: INSERT INTO 表名(字段1,字段2,字段3…) VALUES (值1,值2,值3…); 3. 插入多条记录 语法: INSERT INTO 表名 VALUES (值1,值2,值3…值n), (值1,值2,值3…值n), (值1,值2,值3…值n); 4. 插入查询结果 语法: INSERT INTO 表名(字段1,字段2,字段3…字段n) SELECT (字段1,字段2,字段3…字段n) FROM 表2 WHERE …;
语法: UPDATE 表名 SET 字段1=值1, 字段2=值2, WHERE CONDITION; 示例: UPDATE mysql.user SET password=password(‘123’) where user=’root’ and host=’localhost’;
语法: DELETE FROM 表名 WHERE CONITION; 示例: DELETE FROM mysql.user WHERE password=’’; 练习: 更新MySQL root用户密码为mysql123 删除除从本地登陆的root用户之外的全部用户
from where group by select distinct having order by limit
1.找到表:fromwindows
2.拿着where指定的约束条件,去文件/表中取出一条条记录函数
3.将取出的一条条记录进行分组group by,若是没有group by,则总体做为一组post
4.执行select(去重)编码
5.将分组的结果进行having过滤code
6.将结果按条件排序:order by排序
7.限制结果的显示条数rem
#建立表 create table employee( id int not null unique auto_increment, emp_name varchar(20) not null, sex enum('male','female') not null default 'male', #大部分是男的 age int(3) unsigned not null default 28, hire_date date not null, post varchar(50), post_comment varchar(100), salary double(15,2), office int, #一个部门一个屋子 depart_id int ); #查看表结构 mysql> desc employee; +--------------+-----------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-----------------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | emp_name | varchar(20) | NO | | NULL | | | sex | enum('male','female') | NO | | male | | | age | int(3) unsigned | NO | | 28 | | | hire_date | date | NO | | NULL | | | post | varchar(50) | YES | | NULL | | | post_comment | varchar(100) | YES | | NULL | | | salary | double(15,2) | YES | | NULL | | | office | int(11) | YES | | NULL | | | depart_id | int(11) | YES | | NULL | | +--------------+-----------------------+------+-----+---------+----------------+ #插入记录 #三个部门:教学,销售,运营 insert into employee(emp_name,sex,age,hire_date,post,salary,office,depart_id) values ('egon','male',18,'20170301','办事处',7300.33,401,1), #如下是教学部 ('anwen','male',78,'20150302','teacher',1000000.31,401,1), ('wudi','male',81,'20130305','teacher',8300,401,1), ('yuanhao','male',73,'20140701','teacher',3500,401,1), ('liwen','male',28,'20121101','teacher',2100,401,1), ('jingliyang','female',18,'20110211','teacher',9000,401,1), ('jinxin','male',18,'19000301','teacher',30000,401,1), ('成龙','male',48,'20101111','teacher',10000,401,1), ('歪歪','female',48,'20150311','sale',3000.13,402,2),#如下是销售部门 ('丫丫','female',38,'20101101','sale',2000.35,402,2), ('丁丁','female',18,'20110312','sale',1000.37,402,2), ('星星','female',18,'20160513','sale',3000.29,402,2), ('格格','female',28,'20170127','sale',4000.33,402,2), ('张xx','male',28,'20160311','operation',10000.13,403,3), #如下是运营部门 ('程咬金','male',18,'19970312','operation',20000,403,3), ('程咬银','female',18,'20130311','operation',19000,403,3), ('程咬铜','male',18,'20150411','operation',18000,403,3), ('程咬铁','female',18,'20140512','operation',17000,403,3) ; #ps:若是在windows系统中,插入中文字符,select的结果为空白,能够将全部字符编码统一设置成gbk 准备表和记录
#简单查询 SELECT id,emp_name,sex,age,hire_date,post,post_comment,salary,office,depart_id FROM employee; SELECT * FROM employee; SELECT emp_name,salary FROM employee; #避免重复DISTINCT SELECT DISTINCT post FROM employee; #经过四则运算查询 SELECT emp_name, salary*12 FROM employee; SELECT emp_name, salary*12 AS Annual_salary FROM employee; SELECT emp_name, salary*12 Annual_salary FROM employee; #定义显示格式 CONCAT() 函数用于链接字符串 SELECT CONCAT('姓名: ',emp_name,' 年薪: ', salary*12) AS Annual_salary FROM employee; CONCAT_WS() 第一个参数为分隔符 SELECT CONCAT_WS(':',emp_name,salary*12) AS Annual_salary FROM employee; 结合CASE语句: SELECT ( CASE WHEN emp_name = 'jingliyang' THEN emp_name WHEN emp_name = 'alex' THEN CONCAT(emp_name,'_BIGSB') ELSE concat(emp_name, 'SB') END ) as new_name FROM employee;
小练习:
1 查出全部员工的名字,薪资,格式为 <名字:egon> <薪资:3000> 2 查出全部的岗位(去掉重复) 3 查出全部员工名字,以及他们的年薪,年薪的字段名为annual_year select concat('<名字:',emp_name,'> ','<薪资:',salary,'>') from employee; select distinct depart_id from employee; select emp_name,salary*12 annual_salary from employee;
where字句中能够使用:
#1:单条件查询 SELECT emp_name FROM employee WHERE post='sale'; #2:多条件查询 SELECT emp_name,salary FROM employee WHERE post='teacher' AND salary>10000; #3:关键字BETWEEN AND SELECT emp_name,salary FROM employee WHERE salary BETWEEN 10000 AND 20000; SELECT emp_name,salary FROM employee WHERE salary NOT BETWEEN 10000 AND 20000; #4:关键字IS NULL(判断某个字段是否为NULL不能用等号,须要用IS) SELECT emp_name,post_comment FROM employee WHERE post_comment IS NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment IS NOT NULL; SELECT emp_name,post_comment FROM employee WHERE post_comment=''; 注意''是空字符串,不是null ps: 执行 update employee set post_comment='' where id=2; 再用上条查看,就会有结果了 #5:关键字IN集合查询 SELECT emp_name,salary FROM employee WHERE salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ; SELECT emp_name,salary FROM employee WHERE salary IN (3000,3500,4000,9000) ; SELECT emp_name,salary FROM employee WHERE salary NOT IN (3000,3500,4000,9000) ; #6:关键字LIKE模糊查询 通配符’%’ SELECT * FROM employee WHERE emp_name LIKE 'eg%'; 通配符’_’ SELECT * FROM employee WHERE emp_name LIKE 'al__';
小练习:
1. 查看岗位是teacher的员工姓名、年龄 2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄 3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资 4. 查看岗位描述不为NULL的员工信息 5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资 6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资 7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪 select emp_name,age from employee where post = 'teacher'; select emp_name,age from employee where post='teacher' and age > 30; select emp_name,age,salary from employee where post='teacher' and salary between 9000 and 10000; select * from employee where post_comment is not null; select emp_name,age,salary from employee where post='teacher' and salary in (10000,9000,30000); select emp_name,age,salary from employee where post='teacher' and salary not in (10000,9000,30000); select emp_name,salary*12 from employee where post='teacher' and emp_name like 'jin%';
单独使用GROUP BY关键字分组 SELECT post FROM employee GROUP BY post; 注意:咱们按照post字段分组,那么select查询的字段只能是post,想要获取组内的其余相关信息,须要借助函数 GROUP BY关键字和GROUP_CONCAT()函数一块儿使用 SELECT post,GROUP_CONCAT(emp_name) FROM employee GROUP BY post;#按照岗位分组,并查看组内成员名 SELECT post,GROUP_CONCAT(emp_name) as emp_members FROM employee GROUP BY post; GROUP BY与聚合函数一块儿使用 select post,count(id) as count from employee group by post;#按照岗位分组,并查看每一个组有多少人 强调: 若是咱们用unique的字段做为分组的依据,则每一条记录自成一组,这种分组没有意义 多条记录之间的某个字段值相同,该字段一般用来做为分组的依据
#强调:聚合函数聚合的是组的内容,如果没有分组,则默认一组 示例: SELECT COUNT(*) FROM employee; SELECT COUNT(*) FROM employee WHERE depart_id=1; SELECT MAX(salary) FROM employee; SELECT MIN(salary) FROM employee; SELECT AVG(salary) FROM employee; SELECT SUM(salary) FROM employee; SELECT SUM(salary) FROM employee WHERE depart_id=3;
小练习:
1. 查询岗位名以及岗位包含的全部员工名字 2. 查询岗位名以及各岗位内包含的员工个数 3. 查询公司内男员工和女员工的个数 4. 查询岗位名以及各岗位的平均薪资 5. 查询岗位名以及各岗位的最高薪资 6. 查询岗位名以及各岗位的最低薪资 7. 查询男员工与男员工的平均薪资,女员工与女员工的平均薪资 #题1:分组 mysql> select post,group_concat(emp_name) from employee group by post; #题目2: mysql> select post,count(id) from employee group by post; #题目3: mysql> select sex,count(id) from employee group by sex; #题目4: mysql> select post,avg(salary) from employee group by post; #题目5 mysql> select post,max(salary) from employee group by post; #题目6 mysql> select post,min(salary) from employee group by post; #题目七 mysql> select sex,avg(salary) from employee group by sex;
HAVING与WHERE不同的地方在于!!!!!!
#!!!执行优先级从高到低:where > group by > having #1. Where 发生在分组group by以前,于是Where中能够有任意字段,可是绝对不能使用聚合函数。 #2. Having发生在分组group by以后,于是Having中能够使用分组的字段,没法直接取到其余字段,能够使用聚合函数
select * from emp where salary > 100000; mysql> select post,group_concat(emp_name) from emp group by post having salary > 10000;#错误,分组后没法直接取到salary字段 ERROR 1054 (42S22): Unknown column 'salary' in 'having clause' mysql> select post,group_concat(emp_name) from emp group by post having avg(salary) > 10000;
小练习:
1. 查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数 3. 查询各岗位平均薪资大于10000的岗位名、平均工资 4. 查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资 select post,group_concat(emp_name),count(id) from employee group by post having count(id) < 2; select post,avg(salary) from employee group by post having avg(salary) > 10000; select post,avg(salary) from employee group by post having avg(salary) > 10000 and avg(salary) <20000;
按单列排序 SELECT * FROM employee ORDER BY salary; SELECT * FROM employee ORDER BY salary ASC; SELECT * FROM employee ORDER BY salary DESC; 按多列排序:先按照age排序,若是年纪相同,则按照薪资排序 SELECT * from employee ORDER BY age, salary DESC;
小练习:
1. 查询全部员工信息,先按照age升序排序,若是age相同则按照hire_date降序排序 2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列 3. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列 select * from employee ORDER BY age asc,hire_date desc; select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) asc; select post,avg(salary) from employee group by post having avg(salary) > 10000 order by avg(salary) desc;
示例: SELECT * FROM employee ORDER BY salary DESC LIMIT 3; #默认初始位置为0 SELECT * FROM employee ORDER BY salary DESC LIMIT 0,5; #从第0开始,即先查询出第一条,而后包含这一条在内日后查5条 SELECT * FROM employee ORDER BY salary DESC LIMIT 5,5; #从第5开始,即先查询出第6条,而后包含这一条在内日后查5条
小练习:
select * from employee limit 0,5; select * from employee limit 5,5; select * from employee limit 10,5;
SELECT * FROM employee WHERE emp_name REGEXP '^ale'; SELECT * FROM employee WHERE emp_name REGEXP 'on$'; SELECT * FROM employee WHERE emp_name REGEXP 'm{2}'; 小结:对字符串匹配的方式 WHERE emp_name = 'egon'; WHERE emp_name LIKE 'yua%'; WHERE emp_name REGEXP 'on$';