1, test1表sql
2,test2表ide
3,查询
3d
1,left join (1表为条件)blog
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id1 a2, t2.id2 b2, t2.id id2 FROM test1 t1 LEFT JOIN test2 t2 ON t1.id1 = t2.id2 WHERE t1.id1 = 2
结果:
it
2,left join (2表为条件)class
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id id2, t2.id1 a2, t2.id2 b2 FROM test1 t1 LEFT JOIN test2 t2 ON t1.id1 = t2.id2 WHERE t2.id1 = 2
结果:test
总结:不管是左边 的表仍是右边的表都以显示左边的为主,左边的表能够重复im
3,left join (左边存在右边不存在条件)总结
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id id2, t2.id1 a2, t2.id2 b2 FROM test1 t1 LEFT JOIN test2 t2 ON t1.id1 = t2.id2 WHERE t1.id1 = 6
结果:
数据
3,left join (右边存在左边不存在条件)
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id id2, t2.id1 a2, t2.id2 b2 FROM test1 t1 LEFT JOIN test2 t2 ON t1.id1 = t2.id2 WHERE t2.id1 = 5
结果:
4,left join (查询全部的字段)
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id id2, t2.id1 a2, t2.id2 b2 FROM test1 t1 LEFT JOIN test2 t2 ON t1.id1 = t2.id2
结果:
5,right join (查询全部字段)
SELECT t1.id id1, t1.id1 a1, t1.id2 b1, t2.id id2, t2.id1 a2, t2.id2 b2 FROM test1 t1 RIGHT JOIN test2 t2 ON t1.id1 = t2.id2
结果:
总结:
左链接和右链接正好相反,不介绍了
1,保证数据的完整,只要和左边的表条件对应,都会显示
2,和左边的表不对应,就不显示
3,左边存在显示左边的,右边不存在就不显示
[便于本身理解最好本身手动敲一遍,记忆是经过多个器官共鸣,记忆更加深厚]