Educational Codeforces Round 90 (Rated for Div. 2)

时间 2020-07-26

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Educational Codeforces Round 90 (Rated for Div. 2)c++ E. Sum of Digits 题意：数据范围：1<=n<=150，0<=k<=9git 解法：首先k=0的时候确定是x99999的形式，贪心一下就好了web 其余状况：由于k<10，因此最多进位一次由于不肯定答案是否进位，因此枚举个位，对每种个位都计算一遍答案而后取min 最后答

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1. Educational Codeforces Round 90 (Rated for Div. 2) - G. Pawns
2. Educational Codeforces Round 90 (Rated for Div. 2)题解
3. Educational Codeforces Round 67 (Rated for Div. 2)
4. Educational Codeforces Round 57 (Rated for Div. 2)
5. Educational Codeforces Round 61 (Rated for Div. 2)(题解)
6. Educational Codeforces Round 77 (Rated for Div. 2)
7. Educational Codeforces Round 86 (Rated for Div. 2) A~D
8. Educational Codeforces Round 86 [Rated for Div. 2] Solution
9. Educational Codeforces Round 83 (Rated for Div. 2) D
10. Educational Codeforces Round 64 (Rated for Div. 2)
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1. Educational Codeforces Round 90 (Rated for Div. 2) - G. Pawns
2. Educational Codeforces Round 90 (Rated for Div. 2)题解
3. Educational Codeforces Round 67 (Rated for Div. 2)
4. Educational Codeforces Round 57 (Rated for Div. 2)
5. Educational Codeforces Round 61 (Rated for Div. 2)(题解)
6. Educational Codeforces Round 77 (Rated for Div. 2)
7. Educational Codeforces Round 86 (Rated for Div. 2) A~D
8. Educational Codeforces Round 86 [Rated for Div. 2] Solution
9. Educational Codeforces Round 83 (Rated for Div. 2) D
10. Educational Codeforces Round 64 (Rated for Div. 2)

>>更多相关文章<<