原题连接在这里:https://leetcode.com/problems/peeking-iterator/html
题目:java
Given an Iterator class interface with methods: next()
and hasNext()
, design and implement a PeekingIterator that support the peek()
operation -- it essentially peek() at the element that will be returned by the next call to next().api
Here is an example. Assume that the iterator is initialized to the beginning of the list: [1, 2, 3]
.oracle
Call next()
gets you 1, the first element in the list.ide
Now you call peek()
and it returns 2, the next element. Calling next()
after that still return 2.this
You call next()
the final time and it returns 3, the last element. Calling hasNext()
after that should return false.spa
题解:设计
设计一个是否被peek过得flag, isPeeked with initialization as false.code
同时保存peek过得值peekVal. 若果isPeeked == true 已经peek过,next()直接返回peekVal, hasNext()直接看isPeek为true 就返回 true.htm
Time Complexity: peek, O(1). next, O(1). hasNext, O(1).
Space: O(1).
AC Java:
1 // Java Iterator interface reference: 2 // https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html 3 class PeekingIterator implements Iterator<Integer> { 4 Iterator<Integer> it; 5 boolean isPeeked; 6 int peekVal; 7 8 public PeekingIterator(Iterator<Integer> iterator) { 9 // initialize any member here. 10 this.it = iterator; 11 isPeeked = false; 12 } 13 14 // Returns the next element in the iteration without advancing the iterator. 15 public Integer peek() { 16 if(!isPeeked){ 17 isPeeked = true; 18 if(it.hasNext()){ 19 peekVal = it.next(); 20 }else{ 21 throw new IllegalStateException("iterator doesn't has next value."); 22 } 23 } 24 return peekVal; 25 } 26 27 // hasNext() and next() should behave the same as in the Iterator interface. 28 // Override them if needed. 29 @Override 30 public Integer next() { 31 if(isPeeked){ 32 isPeeked = false; 33 return peekVal; 34 } 35 return it.next(); 36 } 37 38 @Override 39 public boolean hasNext() { 40 return isPeeked || it.hasNext(); 41 } 42 }