NMS(Non-Maximum Suppression)算法本质是搜索局部极大值,抑制非极大值元素。NMS就是须要根据score矩阵和region的坐标信息,从中找到置信度比较高的bounding box。NMS是大部分深度学习目标检测网络所须要的,大体算法流程为:算法
1.对全部预测框的置信度降序排序网络
2.选出置信度最高的预测框,确认其为正确预测,并计算他与其余预测框的IOUapp
3.根据2中计算的IOU去除重叠度高的,IOU>threshold就删除学习
4.剩下的预测框返回第1步,直到没有剩下的为止spa
须要注意的是:Non-Maximum Suppression一次处理一个类别,若是有N个类别,Non-Maximum Suppression就须要执行N次。code
# -------------------------------------------------------- # Fast R-CNN # Copyright (c) 2015 Microsoft # Licensed under The MIT License [see LICENSE for details] # Written by Ross Girshick # -------------------------------------------------------- import numpy as np def py_cpu_nms(dets, thresh): """Pure Python NMS baseline.""" x1 = dets[:, 0] y1 = dets[:, 1] x2 = dets[:, 2] y2 = dets[:, 3] scores = dets[:, 4] areas = (x2 - x1 + 1) * (y2 - y1 + 1) order = scores.argsort()[::-1] #[::-1]表示降序排序,输出为其对应序号 keep = [] #须要保留的bounding box while order.size > 0: i = order[0] #取置信度最大的(即第一个)框 keep.append(i) #将其做为保留的框 #如下计算置信度最大的框(order[0])与其它全部的框(order[1:],即第二到最后一个)框的IOU,如下都是以向量形式表示和计算 xx1 = np.maximum(x1[i], x1[order[1:]]) #计算xmin的max,即overlap的xmin yy1 = np.maximum(y1[i], y1[order[1:]]) #计算ymin的max,即overlap的ymin xx2 = np.minimum(x2[i], x2[order[1:]]) #计算xmax的min,即overlap的xmax yy2 = np.minimum(y2[i], y2[order[1:]]) #计算ymax的min,即overlap的ymax w = np.maximum(0.0, xx2 - xx1 + 1) #计算overlap的width h = np.maximum(0.0, yy2 - yy1 + 1) #计算overlap的hight inter = w * h #计算overlap的面积 ovr = inter / (areas[i] + areas[order[1:]] - inter) #计算并,-inter是由于交集部分加了两次。 inds = np.where(ovr <= thresh)[0] #本轮,order仅保留IOU不大于阈值的下标 order = order[inds + 1] #删除IOU大于阈值的框 return keep